The "C language" adjustment array makes all odd numbers precede even numbers

Adjust the array so that all odd numbers are in front of even numbers. Enter an array of integers to implement a function that adjusts the order of the numbers in the array so that all the odd digits in the array are in the first half of the array, and all the even digits are in the second half of the array # include <stdio.h>void Adjust (int arr[],int  Len) {int I, j;for (i = 0; i < len; i++) {if ((arr[i]%2) ==0) for (j = i + 1; j < Len; J + +) {int temp;if ((Arr[j]% 2) = = 1) {temp = Arr[i];arr[i] = arr[j];arr[j] = Temp;break;}}} int main () {int I;int arr[] = {1, 3, 5, 7, 9, 2, 4, 6, 8, 11}; Adjust (arr, sizeof (arr)/sizeof (arr[0])); for (i = 0; i < sizeof (arr)/sizeof (arr[0]); i++) {printf ("%3d", Arr[i]);} printf ("\ n"); return 0;}

Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced.

The "C language" adjustment array makes all odd numbers precede even numbers