Description
Delimiter (),/,//
(a) B:b,a B is correct. The words in parentheses are optional
(A/b) C:c,a c,b c are correct./before and after the word is or the relationship
A//b:a,b are correct
Requirements:
Converts the combination of words represented by the above symbols into regular notation
Example: ((it is/' s) the/a) CAT//(it is/' s) (the) Animal
Reply to discussion (solution)
Description:
delimiter (),/,//
(a) B:b,a B are correct. The words in parentheses
(A/b) C:c,a c,b c are correct./before and after the word is or off
A//b:a,b are correct
Requirements:
Convert the combination of words represented above into regular notation
Example: ((it is/'s) the/a) CAT//(it is/' s) (the) Animal
don't quite understand what you want to say
First (a) B matches the character "AB", the substring "a"
followed (A/b) C matches the character "A/BC", the substring "A/b"
again a//b matches the string "a//b"
((it is/'s) the/a) CAT//(it is/' s) (the) animal
You want to write a regular expression match
It is a cat
it's the cat br> It's a cat
it's the cat
It is animal
It's the animal
It's animal
It's the animal
?
(It (' S|\s+is) \s+ (a|the) \s+cat) | ( It (' S|\s+is) \s+ (animal|the\s+animal))
Don't quite understand what you're trying to say.
First (a) B matches the character "AB", the substring "a"
Second (A/b) C matches the character "A/BC", the substring "A/b"
Again a//b matches the string "a//b"
((it is/' s) the/a) CAT//(it is/' s) (the) Animal
You want to write a regular expression match
It is a cat
It is the cat
It ' s a cat
It ' s the cat
It is animal
It is the animal
It ' s animal
It ' s the animal
, huh?
Except for those above,
Cat
A cat
The Cat
Animal
The animal
are right.
I want a conversion, a delimiter (),/,//These are convention rules, not regular semantics. Thank you, 1 floor.
Make an example to understand
function Pregrule ($str) { $str = trim ($STR); Return '/^ '. Str_replace (Array (') ', ' [', '] ', '//', '/', '), Array (')? \s* ', ' (', ') {1} ', ' | ', ' | ', ' \s+ '), $str). ' $/'; } $STR = "(a) B"; Echo Pregrule ($str). '
'; $str = "[a//b]"; #加个中括号, easy to convert echo pregrule ($str). '
'; $str = "(A/b) c"; Echo Pregrule ($str). '
'; $str = "((it [is/'s]) the/a CAT//(It [is/' s]) (the) animal"; Echo pregrule ($str). '
';
#result:
/^ (a)? \s*b$/
/^ (a|b) {1}$/
/^ (a|b)? \s*c$/
/^ (it\s+ (is| ' s) {1})? \s*cat\s+|\s+ (it\s+ (is| ' \s*the|a)? s) {1})? \s* (The)? \s*animal$/
The first three kinds of still do, the fourth match will not bear the heart to see, please help enrich this function, so that it can be adapted to appropriate changes in the statement
Make an example to understand
function Pregrule ($str) { $str = trim ($STR); Return '/^ '. Str_replace (Array (') ', ' [', '] ', '//', '/', '), Array (')? \s* ', ' (', ') {1} ', ' | ', ' | ', ' \s+ '), $str). ' $/'; } $STR = "(a) B"; Echo Pregrule ($str). '
'; $str = "[a//b]"; #加个中括号, easy to convert echo pregrule ($str). '
'; $str = "(A/b) c"; Echo Pregrule ($str). '
'; $str = "((it [is/'s]) the/a CAT//(It [is/' s]) (the) animal"; Echo pregrule ($str). '
';
#result:
/^ (a)? \s*b$/
/^ (a|b) {1}$/
/^ (a|b)? \s*c$/
/^ (it\s+ (is| ' s) {1})? \s*cat\s+|\s+ (it\s+ (is| ' \s*the|a)? s) {1})? \s* (The)? \s*animal$/
The first three kinds of still do, the fourth match will not bear the heart to see, please help enrich this function, so that it can be adapted to appropriate changes in the statement
Probably understood.
Why, are you sure that these so-called rules users you set are understood?
You want to do a function like automatic grading, I guess the teacher who set the answer will be confused.
Make an example to understand
function Pregrule ($str) { $str = trim ($STR); Return '/^ '. Str_replace (Array (') ', ' [', '] ', '//', '/', '), Array (')? \s* ', ' (', ') {1} ', ' | ', ' | ', ' \s+ '), $str). ' $/'; } $STR = "(a) B"; Echo Pregrule ($str). '
'; $str = "[a//b]"; #加个中括号, easy to convert echo pregrule ($str). '
'; $str = "(A/b) c"; Echo Pregrule ($str). '
'; $str = "((it [is/'s]) the/a CAT//(It [is/' s]) (the) animal"; Echo pregrule ($str). '
';
#result:
/^ (a)? \s*b$/
/^ (a|b) {1}$/
/^ (a|b)? \s*c$/
/^ (it\s+ (is| ' s) {1})? \s*cat\s+|\s+ (it\s+ (is| ' \s*the|a)? s) {1})? \s* (The)? \s*animal$/
The first three kinds of still do, the fourth match will not bear the heart to see, please help enrich this function, so that it can be adapted to appropriate changes in the statement
The fourth major problem is to replace the words "/" with "|"
A/b
Ca/bd
In the first case, there is no need to think too much directly replace "/" with "|" Just OK.
In the second case, you have to think about it. Do you want to CAD,CBD or want CA,BD? So this time, you can't just consider "/" and replace it with "|".
Here's your fourth expression after the substitution
/^ (it\s+ (is| ' s) {1})? \s*cat\s+|\s+ (it\s+ (is| ' \s*the|a)? s) {1})? \s* (The)? \s*animal$/
Just look at the first half.
((It\s+ (is| ' s) {1})? \s*the|a)? \s*cat\s+ in the
(It\s+ (is| ' s) {1})? \s*the|a)
You want it\s+ (is| ' s) {1})? \s* matches the characters and then stitching the or a
But actually the expression is showing that you want it\s+ (is| ' s) {1})? \s*the or a
You want I want (the|a), but actually you say I want the|a