The SQL statement queries the structure of all tables in the database.

Source: Internet
Author: User

The SQL statement queries the structure of all tables in the database.

</pre><pre name="code" class="sql">SELECT     TableName=CASE WHEN C.column_id=1 THEN O.name ELSE N'' END,    TableDesc=ISNULL(CASE WHEN C.column_id=1 THEN PTB.[value] END,N''),    Column_id=C.column_id,    ColumnName=C.name,    PrimaryKey=ISNULL(IDX.PrimaryKey,N''),    [IDENTITY]=CASE WHEN C.is_identity=1 THEN N'√'ELSE N'' END,    Computed=CASE WHEN C.is_computed=1 THEN N'√'ELSE N'' END,    Type=T.name,    Length=C.max_length,    Precision=C.precision,    Scale=C.scale,    NullAble=CASE WHEN C.is_nullable=1 THEN N'√'ELSE N'' END,    [Default]=ISNULL(D.definition,N''),    ColumnDesc=ISNULL(PFD.[value],N''),    IndexName=ISNULL(IDX.IndexName,N''),    IndexSort=ISNULL(IDX.Sort,N''),    Create_Date=O.Create_Date,    Modify_Date=O.Modify_dateFROM sys.columns C    INNER JOIN sys.objects O        ON C.[object_id]=O.[object_id]            AND O.type='U'            AND O.is_ms_shipped=0    INNER JOIN sys.types T        ON C.user_type_id=T.user_type_id    LEFT JOIN sys.default_constraints D        ON C.[object_id]=D.parent_object_id            AND C.column_id=D.parent_column_id            AND C.default_object_id=D.[object_id]    LEFT JOIN sys.extended_properties PFD        ON PFD.class=1             AND C.[object_id]=PFD.major_id             AND C.column_id=PFD.minor_id--             AND PFD.name='Caption'      LEFT JOIN sys.extended_properties PTB        ON PTB.class=1             AND PTB.minor_id=0             AND C.[object_id]=PTB.major_id--             AND PFD.name='Caption'      LEFT JOIN                          (        SELECT             IDXC.[object_id],            IDXC.column_id,            Sort=CASE INDEXKEY_PROPERTY(IDXC.[object_id],IDXC.index_id,IDXC.index_column_id,'IsDescending')                WHEN 1 THEN 'DESC' WHEN 0 THEN 'ASC' ELSE '' END,            PrimaryKey=CASE WHEN IDX.is_primary_key=1 THEN N'√'ELSE N'' END,            IndexName=IDX.Name        FROM sys.indexes IDX        INNER JOIN sys.index_columns IDXC            ON IDX.[object_id]=IDXC.[object_id]                AND IDX.index_id=IDXC.index_id        LEFT JOIN sys.key_constraints KC            ON IDX.[object_id]=KC.[parent_object_id]                AND IDX.index_id=KC.unique_index_id        INNER JOIN          (            SELECT [object_id], Column_id, index_id=MIN(index_id)            FROM sys.index_columns            GROUP BY [object_id], Column_id        ) IDXCUQ            ON IDXC.[object_id]=IDXCUQ.[object_id]                AND IDXC.Column_id=IDXCUQ.Column_id                AND IDXC.index_id=IDXCUQ.index_id    ) IDX        ON C.[object_id]=IDX.[object_id]            AND C.column_id=IDX.column_id ORDER BY O.name,C.column_id 


Related Article

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.