The sqrt of Leetcode

Source: Internet
Author: User

Implement int sqrt(int x) .

Compute and return the square root of X.

This problem also belongs to the transformation of the binary search

The mainstream approach is to use Newton's interpolation, the idea of Newton's method to refer to

Attach the code to the following:

public int sqrt (int x) {        if (x = = 1) return 1;double res = x/2;while (Math.Abs (res * res-x) > 0.00001) {res = (r ES + x/res)/2;} return (int) res;    

The last few days began to lazy, no NO!!!! Insist on sticking to

The sqrt of Leetcode

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