Then the value of expression x = 1 y = x + 3/2 is 2.0 C language: If the X and Y types are defined as double

The result of 2.3/2 is that when the value of 1 of int is assigned to the X of double, it is automatically upgraded to the value of double type. 1 is of the int type.

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It seems that the results of float and double calculation will contain. 0. If int, there will be no such results.

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If it is defined as int type (integer), the value of the defined integer is 2 double type (floating point type) yes. The defined y value of the defined real number can only be of the 2.0doudle type. The defined range is larger than that of the int type.

1. X = 1 first, increase the 1 of int to 1.0 of double, and then the X of double plus the 1 of int, so x = 1.0 (note that 1.0 is of the double type) then x + 1.0 = 2.0 (2.0 is double type)