# There are multiple arrays. how many combinations can be calculated and obtained ?? -Php Tutorial

Source: Internet
Author: User
There are multiple arrays. how many combinations can be calculated and obtained ?? Array A, B, C, D
The count in the table is not necessarily the same.
The combination order is fixed. A [rand] + B [rand] + C [rand] + D [rand] = no repeated strings.
How can I obtain the maximum number of combinations and no repeated strings ??

This post was last edited by xuzuning at 23:59:51 on

Quantity = count (A) * count (B) * count (C) * count (D)

`\$a = array('a1', 'a2');\$b = array('b1', 'b2');\$c = array('c1', 'c2', 'c3');\$d = array('d1', 'd2', 'd3');print_r(func(\$a, \$b, \$c, \$d));function func() {  \$d = func_get_args();  \$r = array_shift(\$d);  while(\$d) {    \$t = array();    foreach(array_shift(\$d) as \$x)      foreach(\$r as \$y) \$t[] = \$y . \$x;    \$r = \$t;  }  return \$r;}`
Array
(
[0] => a1b1c1d1
[1] => a2b1c1d1
[2] => a1b2c1d1
[3] => a2b2c1d1
[4] => a1b1c2d1
[5] => a2b1c2d1
[6] => a1b2c2d1
[7] => a2b2c2d1
[8] => a1b1c3d1
[9] => a2b1c3d1
[10] => a1b2c3d1
[11] => a2b2c3d1
[12] => a1b1c1d2
[13] => a2b1c1d2
[14] => a1b2c1d2
[15] => a2b2c1d2
[16] => a1b1c2d2
[17] => a2b1c2d2
[18] => a1b2c2d2
[19] => a2b2c2d2
[20] => a1b1c3d2
[21] => a2b1c3d2
[22] => a1b2c3d2
[23] => a2b2c3d2
[24] => a1b1c1d3
[25] => a2b1c1d3
[26] => a1b2c1d3
[27] => a2b2c1d3
[28] => a1b1c2d3
[29] => a2b1c2d3
[30] => a1b2c2d3
[31] => a2b2c2d3
[32] => a1b1c3d3
[33] => a2b1c3d3
[34] => a1b2c3d3
[35] => a2b2c3d3
)

Good code. SOLVED. thank you.

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