Three common methods for JavaScript array de-weight and their performance comparison

Source: Internet
Author: User
Tags javascript array

In the array operation often encounter the problem of removing duplicates, the following is a brief introduction to the method of array deduplication, and its implementation efficiency

Method One
Use two loops
Principle: Take the current and the ratio behind him, if there are duplicates on the back to kill
But we found the last item in the array, and there was nothing behind it, so he didn't have to compare it with the back, so we just had to loop arr.length-1 times.

vararr=[1,3,5,3,5,3,4,1,3,5,3,5,3,41,3,5,3,5,3,4,1,3,5,3,5,3,4];  for(vari=0;i<arr.length-1;i++){                       varCuritem=arr[i];//Current Item                        for(varj=i+1;j<arr.length;j++){                               if(curitem==Arr[j]) {Arr.splice (J,1); J--; }}} console.log (arr);

This method uses two cycles, which put a lot of pressure on the browser, the number of times the factorial of the length of the array.

So consider an object substitution (the object's property name is not duplicated) method two

 var  arr=[1,3,5,3,5,3,4,6,2,2,2,1];         var  len=arr.length;         var  obj={};  for  (var  I=0;i<len;i++ var  cur=arr[i]; //         current item  obj[cur]=cur;         var  list=[];  for  (Key in   obj) {List.push (Obj[key])} console.log (list);  

This method performs more efficiently, but loops two times

Take another approach: Method three

Principle: The loop array, which saves each item in the array as the property name and attribute value of the Obj object,
But we found that if the property name already exists in the Obj object, it means that the array is duplicated, so we delete the duplicates.

        vararr=[1,3,5,3,5,3,4,1,3,5,3,5,3,41,3,5,3,5,3,4,1,3,5,3,5,3,4]; varobj={};  for(vari=0;i<arr.length;i++){            varCur=arr[i];//Current Item            if(obj[cur]==cur) {Arr.splice (i,1); I--            }Else{Obj[cur]=cur; }} obj=NULL;    Console.log (arr); 

This method also uses two cycles, thinking carefully about how to use a single implementation of the method of de-weight.

Method Two Encapsulation method

vararr=[1,3,5,3,5,3,4,6,2,2,2,1,7,84,34,634]; Array.prototype.arr_unique=function (){    varlen= This. Length; varobj={};  for(vari=0;i<len;i++){        varCur= This[i];//Current Itemobj[cur]=cur; }    varlist=[];  for(Keyinchobj) {List.push (Obj[key])}returnlist;}; Console.log (Arr.arr_unique ());

Method Three Encapsulation method

        vararr=[1,3,5,3,5,3,4,6,2,2,2,1,7,84,34,634]; Array.prototype.arr_unique=function (){             varobj={};  for(vari=0;i< This. length;i++){                 varCur=arr[i];//Current Item                 if(obj[cur]==cur) {Alert (1111); Arr.splice (i,1); I--                 }Else{Obj[cur]=cur; }} obj=NULL; return  This;         };    Console.log (Arr.arr_unique ()); 

Three common methods for JavaScript array de-weight and their performance comparison

Related Article

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.