To be solved: make lowercase letters uppercase by setting the 6th bit to 0

According to the definition of the UNICODE/ASCII character set, the difference between lowercase letters and uppercase letters is only 32 larger than the latter. So......

1 classUpCase {2      Public Static voidMain (string[] args) {3         Charch;4         5          for(inti = 0; I < 10; i++) {6CH = (Char) (' a ' +i);7 System.out.print (CH);8             9             //This statement turns off the 6th bit.TenCH = (Char) ((int) Ch & 65503);//CH is now uppercase One              ASystem.out.print (ch + ""); -         } -     } the}

The program output is as follows:

AA BB CC dD eE fF gG HH II JJ

The value used in the & statement 65 503 represents 1111 1111 1101 1111 in the binary. Therefore, bitwise AND operation will only allow the 6th bit in ch to be set to 0, while all other bits are unchanged.

To be solved: make lowercase letters uppercase by setting the 6th bit to 0