To find the maximum sub matrix and the maximum sub matrix

To find the maximum sub matrix: The implementation code is as follows

Package com.threeTop.www; The public class Maxsummatrix {/** * Gets the maximum and sub matrix of the matrix * @param matrix * @return/public static int Maxsumsubmatrix
	(int [][]matrix)
		{Int[][]total=matrix;
			for (int i=1;i<matrix.length;i++) {for (int j=0;j<matrix[0].length;j++) {total[i][j]+=total[i-1][j];
		} int maximum=integer.min_value; for (int i=0;i<matrix.length;i++) {for (int j=i;j<matrix.length;j++) {//result saved is from line I to J line known as element worthy and in
				
				t []result=new Int[matrix[0].length];
					for (int k=0;k<matrix[0].length;k++) {if (i==0) {result[k]=total[j][k];
					}else {result[k]=total[j][k]-total[i-1][k];
				
			    }//Call Fetch sub array and maximum function int Maximal=maxsubarray (result);
			    if (maximal>maximum) {maximum=maximal;
	}} return maximum;
		/** * Dynamic programming to find the largest sub array * @param result * @return/private static int Maxsubarray (int[] result) {int lastsum=0; int Maxsum=resulT[0];
			for (int i=0;i<result.length;i++) {if (lastsum>0) {//additive lastsum=lastsum+result[i];
			
			}else {///If a new starting point is required, the value of start Lastsum=result[i is assigned;
			
			} if (maxsum<lastsum) {maxsum=lastsum;
	} return maxsum;
		public static void Main (String[]args) {int [][]matrix={{-1,2,-1,3,-4},{2,3,4,-5,1},{1,-1,5,-3,-2}};
		SYSTEM.OUT.PRINTLN ("Maximum sub Matrix and for:");
		
	System.out.println (Maxsummatrix.maxsumsubmatrix (matrix));
 }
}