Today for the first time to interview, there are many questions can not answer, please the Great God Advice

The first time I went to the interview, I found a lot different from the textbook.
3. A brief introduction to hibernate?
8. Can you familiarize yourself with the configuration of the James server? And how much does the docs command remember? Project
11. How did Java development turn into PHP development?
What is the difference between 14.InnoDB and MyISAM?
15. Use the EL expression to write the path to the URL.
These questions, some even the name do not know, feel a very wide test, ask the great God advice

Reply to discussion (solution)

Are you interviewing for Java or PHP? Basic Java Knowledge points

I'm going to interview PHP, and I don't know how to do these written questions.

What is the difference between 14.InnoDB and MyISAM?

This should do it.

Can you give me a brief description of the answer? Baidu's answer is so esoteric.

What's the difference between InnoDB and MyISAM?
InnoDB support transaction, MYISAM not supported
InnoDB Slow, MyIsAm fast
InnoDB cannot be copied directly, MyIsAm can be copied directly

As for Java-related problems, there's no need to answer them here.
1, you are not learning Java
2, this is the PHP discussion area, Java issues should be discussed in the Java discussion area. The surgery industry has a specialization.

InnoDB supports row-level locks and has advantages over MyISAM in high-concurrency write situations
InnoDB count () is traversed every time
It doesn't look like a PHP interview.

I feel very innocent, obviously I was to interview PHP, but part of the question is java.
There is my work experience lost to others, I look at the next few are filled 1-5 years of work experience, only I am a fresh graduate.
I would also like to fill in 1 years of work experience, but the following to fill the work place, name, position and other information, this I can't pull out, can only honestly fill the fresh graduates
Fill out the form, after a while is HR, it's not a good interview. Because I am a fresh graduate, my project experience is only filled with two. The interviewer told me that at least 5, 6. I think two or three is already enough, and during the laugh, do exercises and take no shot, counted on the project only two graduation project.
Forget it, say more is tears.

For the customer authorization, in the case of authorization, the display of customer information, unauthorized, customers can not access, according to their own ideas about how to do the function?
How can this be achieved?
(My train of thought: When the customer authorizes, creates a new session, stores the customer's information.) If authorization is canceled, the session's validity period is set to-1, and unauthorized sessions are not created.

Long to see the only know InnoDB and MyISAM what is the difference? The drifting over

The so-called customer authorization should be to the customer rating, different levels corresponding to different permissions on OK.

Web page appears 302,403,500, what is the meaning of each?

These are the primary programmer's face questions. The status code represents the server return value. Baidu next A lot

Learn to use search engines to learn! These questions are not difficult, Baidu, Google a random search, you can search a lot of answers.

Web page appears 302,403,500, what is the meaning of each?

Http://baike.baidu.com/link?url=fX5X_WN4wYoCxWePAOFa3PlXyHsdBj6kkN0qwuLbqYQX5PycV5jf8uRJO1JcazGtQZaTH7x-0BEX4r3261JWe_

About the authorization, the permanent preservation is good, only establishes the conversation, finally has the expiration day.

Thanks for the moderator's advice
$a = "ABCD";
$b = "DCSE";

$a = $a ^ $b;
$b = $b ^ $a;
$a = $b ^ $a;

Exchanging the value of a variable with a bitwise operator is one of the views that I see confused.

$a ^ $b Xor (Bitwise XOR) sets the $a and $b one to 1 and the other 0 to 1.
(I have to understand that if these two variables are empty, one is not empty then return 1)

I looked at some examples, and tried a few values
echo 12 ^ 9; Output is 5
Echo 12^10;//6
Echo 12^12;//0
I can't see what the rules are, please advise us

The previous problems have been basically solved, please help to see this problem

Thanks for the moderator's advice
$a = "ABCD";
$b = "DCSE";

$a = $a ^ $b;
$b = $b ^ $a;
$a = $b ^ $a;

Exchanging the value of a variable with a bitwise operator is one of the views that I see confused.

$a ^ $b Xor (Bitwise XOR) sets the $a and $b one to 1 and the other 0 to 1.
(I have to understand that if these two variables are empty, one is not empty then return 1)

I looked at some examples, and tried a few values
echo 12 ^ 9; Output is 5
Echo 12^10;//6
Echo 12^12;//0
I can't see what the rules are, please advise us

echo 12 ^ 9; Output is 5
Echo 12^10;//6
Echo 12^12;//0

First turn 2 binary, in the operation of XOR.
XOR operation, Same bit = 0-bit different =1
For example, the binary of 12 is
1100
The binary of 9 is
101
Then 12 ^ 9 equals, Bitwise XOR or
1100
0101
Concluded
1001
Decimal =9 of 1001

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