Arkady plays gardenscapes a lot. Arkady wants to build and new fountains. There is n available fountains, for each fountain it beauty and cost is known. There is, types of money in the game:coins and diamonds, so each fountain cost can be either in coins or diamonds. No Money changes between the types is allowed.
Help Arkady to find, fountains with maximum total beauty so, he can buy both at the same time.
Input
The first line contains three Integers n , C and D (2?≤? N ? ≤?100?000, 0?≤? C ,? d ? ≤?100?000) -the number of fountains, the number of coins and diamonds Arkady has.
The next n lines describe fountains. Each of these lines contain II integers bi and pi (1?≤? bi,? Pi≤?100?000)-the beauty and the cost of the I-th Fountain, and then a letter " c "or" D ", describing in which type of money are the cost of Fountain i: in coins or in diamonds, re spectively.
Output
Print The maximum total beauty of exactly-fountains Arkady can build. If He can ' t build the fountains, print 0.
Example
Input
3 7 6
8 C
4 3 C
5 6 D
Output
9
Input
2 4 5
2 5 C
2 1 D
Output
0
Input
3 10 10
5 5 C
5 5 C
Ten D
Output
10
Note
In the first example Arkady should build the second fountain with beauty 4, which costs 3 coins. The first fountain he can ' t build because he don ' t has enough coins. Also Arkady should build the third fountain with beauty 5 which costs 6 diamonds. Thus The total beauty of built fountains is 9.
In the second example there is the fountains, but Arkady can ' t build both of them, because he needs 5 coins for the F Irst Fountain, and Arkady have only 4 coins.
1#include <iostream>2#include <string>3#include <algorithm>4#include <cstring>5#include <cstdio>6#include <cmath>7#include <queue>8#include <Set>9#include <map>Ten#include <list> One#include <stack> A #defineMP Make_pair -typedefLong Longll; -typedef unsignedLong Longull; the Const intmax=1e5; - Const intinf=1e9+5; - Const Doublem=4e18; - using namespacestd; + Const intmod=1e9+7; -typedef pair<int,int>PII; + Const Doubleeps=0.000000001; A intc[max+5],d[max+5]; at voidAddint*tree,intKintnum) - { - while(k<=MAX) - { -tree[k]=Max (tree[k],num); -k+=k& (-k); in } - } to intReadint*tree,intk) + { - intRe=0; the while(k) * { $Re=Max (re,tree[k]);Panax Notoginsengk-=k& (-k); - } the returnre; + } A intn,c,d,b,p; the intAn,tem; + Charopt[Ten]; - intMain () $ { $scanf"%d%d%d",&n,&c,&d); - while(n--) - { thescanf"%d%d%s",&b,&p,opt); -tem=0;Wuyi if(opt[0]=='C') the { - if(p>c) Wu Continue; -re+=read (d,d); AboutTem=max (Tem,read (c,c-p)); $ Add (c,p,b); - } - Else - { A if(p>d) + Continue; there+=read (c,c); -Tem=max (Tem,read (d,d-p)); $ Add (d,p,b); the } the if(TEM) theAn=max (an,tem+b); the } -printf"%d\n", an); in return 0; the}
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The first time to write bit, feel more than the line number of lines tree code is indeed much less, but now more complex operation is not written with bit ...
(Tree-like array) codeforces Round #413 c-fountains