U Calculate e factorial addition and summation problem

Question: (n < 10) write an algorithm

Reply:

Method One:

#include <stdio.h>
int main ()
{
int f[10]={1,1,2,6,24,120,720,5040,40320,362880};
int n;
Double E;
printf ("N e\n");
printf ("------------\ n");
printf ("%d%d\n", 0, 1);
printf ("%d%d\n");
printf ("%d%.1f\n", 2,2.5);
e=2.5;
for (n=3;n<=9;n++)
{
E+=1.0/f[n];
printf ("%d%0.9f\n", n,e);
}
return 0;
}

Method Two: #include <cstdio>  
#include <cstring>  
#include <cmath> 
Int main () { 
    double E;  
    int i, TMP;  
    e = 1; & nbsp
    tmp = 1;  
    printf ("N e\n");  
    printf ("-- ---------\ n ");  
    printf ("0 1\n");  
    for (i = 1; i < ten; i++) { 
 &n bsp;      tmp *= i;  
        e + = 1.0/tmp;  
         if (i>=3) printf ("%d%.9lf\n", I, E);  
        else if (2 = = i) printf ("%d%.1lf\n", I, e);  
         else printf ("%d%.0lf\n", I, E);  
   }  
    return 0;  
}

Many methods, original aim, mainly output to pay attention to the format and range on the line.

U Calculate e factorial addition and summation problem