Use Java to complete conversion of decimal to binary octal hexadecimal

/*

hexadecimal conversions

Requirements:

1. Input data from keyboard (with input prompt)

2. Using custom methods

Increase:

For the number of inputs, the conversion is 8-and 2-binary.

*/

Import Java.util.Scanner;

public class arraytest{

public static void Main (string[] args) {

System.out.print ("Please enter a number to convert to 16 binary:");

Scanner scan=new Scanner (system.in);

int num = Scan.nextint ();

System.out.print ("converted 16 binary number is:");

Gethex (num);

System.out.println ();

System.out.print ("Converted 2 binary number is:");

Getbinary (num);

System.out.println ();

System.out.print ("Converted 8 binary number is:");

Getoctal (num);

}

Gethex method. Complete the 16 binary conversion function.

Start Gethex;

public static void Gethex (int num) {

char[] chs={' 0 ', ' 1 ', ' 2 ', ' 3 ', ' 4 ', ' 5 ', ' 6 ', ' 7 ', ' 8 ', ' 9 ',

' A ', ' B ', ' C ', ' D ', ' E ', ' F '};

char[] arr = new Char[8];

int p = arr.length; The//int type is 4 bytes in memory, 32 2 binary bits, and the corresponding hexadecimal bit is 8. Each 4 bits corresponds to one digit 16 decimal number.

if (num = = 0) {

System.out.print ("0");

return; //Return here and end this method when the received data is 0.

}

while (num! = 0) {

int x = num & 15;

ARR[--P] = chs[x]; //In the process of saving, starting from the highest bit. This is the first number to be calculated, and the last one to be stored in the array.

num = num >>> 4;   //Move num to the right by 4 2 binary bits. >>> code unsigned Right shift. >> represents a signed shift.

}

for (int i=p;i<arr.length;i++) {//The output process starts from a valid bit. With 0 not output

System.out.print (Arr[i]);

}

}

End Gethex

Start Getoctal

public static void getoctal (int num) {

char[] chs={' 0 ', ' 1 ', ' 2 ', ' 3 ', ' 4 ', ' 5 ', ' 6 ', ' 7 '};

Char[] Arr=new char[11];

int p=arr.length;

if (num = = 0) {

System.out.print ("0");

return;

}

while (num! = 0) {

int N=num & 7;

ARR[--P] = Chs[n];

num = num >>> 3;

}

for (int i=p;i<arr.length;i++) {

System.out.print (Arr[i]);

}

}

End Getoctal

Start Getbinary

public static void getbinary (int num) {

char[] chs={' 0 ', ' 1 '};

Char[] Arr=new char[32];

int p=arr.length;

if (num = = 0) {

System.out.print ("0");

return;

}

while (Num!=0) {

int N=num & 1;

Arr[--p]=chs[n];

num = num >>>1;

}

for (int i=p;i<arr.length;i++) {

System.out.print (Arr[i]);

}

}

End Getbinary

}

Use Java to complete conversion of decimal to binary octal hexadecimal