Use Python to complete SHUANGSE Qiu programs __python

Using Python to complete a shuangse Qiu program

The program can implement this function, but the algorithm should not be the best, if there is a better algorithm, please comment

Import random balls = [] #创建一个空列表
RedBall = List (range (1,34)) #创建红色球的列表
BlueBall = List (range (1,17)) #创建蓝色球的列表
For I in range (6):
x = Random.choice (redball) #每次从红色球里随机取出一个
If x not in balls: #判断取出的球在列表ball是否存在, if it does not exist, add it to the list
Balls.append (x)
If Len (balls)!= 6: #随机数可能存在取出来重复的数字, 6 times after the cycle to determine whether the list length is 6
y = Random.choice (RedBall) #如果不等于6, and then continue from the red ball list to remove a
If Y not in balls: #判断新取出来的是否在balls列表里
Balls.append (y) #不在里面就加进去
Balls.sort () #前面取出来的6个数字是无序的, General Shuangse Qiu are from small to large out

Balls.append (Random.choice (blueball)) #最后将蓝色球随机取出来一个放到列表里

Print (balls)

[3, 9, 14, 23, 26, 32, 8] would it not be possible to come out of this, accidentally in the 5 million

Note: The program will still appear when the red ball randomly taken, appeared several times to take out the same ball, I only made a judgment is equal to 6, then can only add one to the balls, this time will appear to take a total of less than 7 balls

Improved procedures:

Import Random
Balls = []
RedBall = List (range (1,34))
BlueBall = List (range (1,17))
For I in range (6):
x = Random.choice (RedBall)
If x not in balls:
Balls.append (x)
For j in Range (5):
If Len (balls)!= 6:
y = Random.choice (RedBall)
If Y not in balls:
Balls.append (y)
Else
Break
Balls.sort ()
Balls.append (Random.choice (BlueBall))
Print (balls)

[5, 11, 13, 27, 31, 32, 4]