Use regular expressions s to match spaces, always less match a space

$ABC = "TC,           M1"; $abc = Ereg_replace (", [\s]+", ",", $ABC); Echo $abc;

The above code is to remove the comma in the string str after the space, the expected result is "Tc,m1"
But the actual operation of the result is "TC, M1", between the comma and M1 more than one space, is why?

Reply to discussion (solution)

$ABC = ' TC,           M1 '; $abc = Preg_replace ("/,[\s]+/", ",", $ABC); echo "
$abc ";

Try, use preg_replace, the result is correct, there is no space, this is why

Ereg function Group is already in the abolition of the column, no need to tangle

$ABC = "TC,           M1"; $a =str_replace (",", $abc); Echo $a;

Tc,m1

Besides, Ereg has no \s.

It is recommended that you use Preg_replace, this function is faster.

Be sure to use ereg_replace, you can instead:
$ABC = Ereg_replace (", []+", ",", $ABC);

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