Using Jsonobject to generate JSON in Java

JSON is a lightweight data interchange format that is very common in today's web development. In the absence of convenient tools, we may use the form of a spelling string to generate a JSON array, today we use a Json-lib.jar package for us to implement the function of generating JSON.

The necessary packages are:

Commons-httpclient-3.1.jar

Commons-lang-2.4.jar

Commons-logging-1.1.1.jar

Json-lib-2.4-jdk15.jar

Ezmorph-1.0.6.jar

Commons-collections-3.2.1.jar

1. The bean is converted to JSON

User U = new user (); U.setage (22);

U.setusername ("HZUCMJ"); U.setenabled (TRUE);

Jsonobject json = jsonobject.fromobject (u);

System.out.println (Json.tostring ());

The result is:

{"Enabled": True, "username": "HZUCMJ", "Age": 22}

2. List is converted to JSON

User U1 = new user (); U1.setage (22);

U1.setusername ("HZUCMJ");

U1.setenabled (TRUE);

User U2 = new user ();

U2.setage (20); U2.setusername ("CTF");

U2.setenabled (TRUE);

list<object> list = new arraylist<object> ();

List.add (U1);

List.add (U2);

Jsonarray json = jsonarray.fromobject (list);

System.out.println (Json.tostring ());

The result is:

[{"Enabled": False, "username": "CTF", "Age": 20},{"Enabled": False, "username": "", "Age": 0}]

3. Map to JSON

hashmap<string, comparable> map = new hashmap<string, comparable> ();

Map.put ("name", "HZUCMJ"); Map.put ("Age", 22);

Jsonobject json = jsonobject.fromobject (list);

System.out.println (Json.tostring ());

The result is:

{"Name": "HZUCMJ", "Age": 22}

Based on the Json-lib.jar packet Jsonobject-java common four kinds of usage

Based on Json-lib.jar package JSON

Instance Program 1.

Jsonobject to Dynabean String json = "{name=\" json\ ", bool:true,int:1,double:2.2}";

Jsonobject Jsonobject = Jsonobject.fromobject (JSON);

Abstract notation:

Dynabean bean = (dynabean) Jsonserializer.tojava (jsonobject);

Object bean = Jsonobject.tobean (jsonobject);

Object bean1 = Jsonserializer.tojava (Jsonobject);

Assertequals (Jsonobject.get ("name"), Propertyutils.getproperty (Bean, "name"));

Assertequals (Jsonobject.get ("bool"), Propertyutils.getproperty (Bean, "bool"));

Assertequals (Jsonobject.get ("int"), Propertyutils.getproperty (Bean, "int"));

Assertequals (Jsonobject.get ("Double"), Propertyutils.getproperty (Bean, "double"));

2.JSONObject to JavaBean String json = "{name:\" zhangsan\ ", age:25,hight:1.72,sex:true}";

Jsonobject Jsonobject = Jsonobject.fromobject (JSON);

UserBean bean = (UserBean) Jsonobject.tobean (Jsonobject, Userbean.class);

System.out.println (Jsonobject);

Theoretically, this would be possible, but when there was an anomaly caused by:java.lang.nosuchmethodexception:com.json.json$userbean.<init> ()

3.JSONArray to List String json = "[\" first\ ", \" second\ "]";

Jsonarray Jsonarray = (jsonarray) Jsonserializer.tojson (JSON);

List output = (list) Jsonserializer.tojava (Jsonarray);

4.JSONArray to array String json = "[\" first\ ", \" second\ "]";

Jsonarray Jsonarray = (jsonarray) Jsonserializer.tojson (JSON);

Jsonconfig jsonconfig = new Jsonconfig ();

Jsonconfig.setarraymode (Jsonconfig.mode_object_array);

object[] output = (object[]) Jsonserializer.tojava (Jsonarray, jsonconfig);

Object[] expected = new object[] {"First", "second"};

Arrayassertions.assertequals (expected, output);

Using Jsonobject to generate JSON in Java