Using Python to determine prime numbers is simple

This article describes how to use Python to determine prime numbers, python, which is often used for scientific computation, handles this small problem. of course, you can refer to this article to explain how to use Python to determine prime numbers, python, which is often used for scientific computing, handles this small problem.

Prime number. In a natural number greater than 1, except for 1 and the integer itself, it cannot be divisible by other natural numbers. Prime numbers play an important role in number theory. A number larger than 1 but not a prime number is called a union number. 1 and 0 are both non-prime numbers and non-composite numbers. Prime numbers are two concepts that are opposite to Union numbers. they constitute one of the most basic definitions in number theory. The problems created based on the definition of prime numbers have many world-class problems, such as the godebach conjecture. The basic arithmetic theorem proves that each positive integer greater than 1 can be written as the product of a prime number, and the product form is unique. The important point of this theorem is that 1 is excluded from the prime number set. If 1 is considered as a prime number, these strict interpretations have to add some restrictions. A friend occasionally asked python how to determine the prime number, checked it online, and summarized several methods for the python script to determine whether a number is a prime number:

1. use python mathematical functions

import math def isPrime(n):   if n <= 1:   return False   for i in range(2, int(math.sqrt(n)) + 1):   if n % i == 0:     return False   return True

2. single-line program scanning Prime numbers

from math import sqrt N = 100 [ p for p in  range(2, N) if 0 not in [ p% d for d in range(2, int(sqrt(p))+1)] ]

Use the itertools module of python

from itertools import count def isPrime(n): www.jb51.net  if n <= 1:     return False   for i in count(2):     if i * i > n:       return True     if n % i == 0:       return False

3. two methods without using modules
Method 1:

def isPrime(n):   if n <= 1:     return False   i = 2   while i*i <= n:     if n % i == 0:       return False     i += 1   return True

Method 2:

def isPrime(n):   if n <= 1:     return False   if n == 2:     return True   if n % 2 == 0:     return False   i = 3   while i * i <= n:     if n % i == 0:       return False     i += 2   return True

Eg: obtain the prime number between 20001 and 40001)
Since it can only be rounded out by one or itself, it means that when the remainder of two times is 0, the code is as follows:

#!/usr/bin/pythonL1=[]for x in xrange(20001,40001): n = 0 for y in xrange(1,x+1): if x % y == 0:  n = n + 1 if n == 2 : print x L1.append(x)print L1

The result is as follows:

2001120021200232002920047200512006320071200892010120107201132011720123201292014320147201492016120173….

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