Using Python to implement the login interface, allowing to try three times

Project Requirements Description: Require the user to enter a user name and password, after the successful authentication display welcome information, if the consecutive error three times to lock the user name.

Logical Flowchart:

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Implementation code:

#!/usr/bin/env pythonimport sysaccount_file =  ' account.txt ' lock_file =  ' lock.txt ' # put accounts in a listfh_account = open (account_file) account_list =  fh_account.readlines () fh_account.close () # initialize retry count as 3 for  every accountretry_count = {}for line in account_list:     line = line.split ()     retry_count[line[0]] = 3while true:     # put locked accounts in a list     Fh_lock = open (Lock_file)     lock_list = []    for  i in fh_lock.readlines ():        line =  I.strip (' \ n ')         lock_list.append (line)     fh_ Lock.close ()     # handle the username and password empty issue     username = raw_input (' username:  '). Strip ()     if len ( username)  == 0:        print  ' \033[31;1musername  should not be empty !\033[0m '         continue     password = raw_input (' password:  '). Strip ()     if  len (password)  == 0:        print  ' \033[31; 1mpassword should not be empty !\033[0m '          continue    # authentication part    if username  in lock_list:        print  "\033[31;1msorry,  '%s '  is locked already ! \033[0m " % username        continue     If not retry_count.has_key (username):   # inexistent account         retry_count[username] = 3    for line  in account_list:        line = line.split ()          if username == line[0] and password ==  line[1]: # authentication pass             retry_count[username] = 3       # reset  retry times for this account             sys.exit (' \033[32;1mwelcome %s login my system !\033[0m '  %  username)     else:                                     # authentication failed        print  ' \033[ 31;1mwrong username or password !\033[0m '          retry_count[username] -= 1        if retry_count[ username] > 0:            print  ' \033[31;1myou have %d more chances !\033[0m '  % retry_count[username]         else:             fh = open (lock_file,  ' a ')              fh.write ('%s\n '  % username)             fh.close ()             print  "\033[31;1msorry,  '%s '  is locked !\033[0m " % username

Using Python to implement the login interface, allowing to try three times