Using UUID in spring data JPA

How to define a uuid in an entity, needless to say

defined in the Entity public class Baseentity.java

import javax.persistence.generatedvalue;import javax.persistence.id;import  javax.persistence.mappedsuperclass;import org.hibernate.annotations.genericgenerator;import  org.springframework.data.domain.persistable;import org.apache.commons.lang3.builder.tostringbuilder; import org.apache.commons.lang3.builder.tostringstyle;/** *  entity public class, all entities inherit the object  * @ author youway */@MappedSuperclasspublic  abstract class baseentity implements  persistable<string> {private static final long serialversionuid =  1L; @Id @generatedvalue (generator =  "System-uuid") @GenericGenerator (name =  " System-uuid ", strategy = " UUID ") Private string id;public string getid ()  {return id;} Protected void setid (Final string id)  {this.id = id;} Public boolean isnew ()  {return this.id ==&Nbsp;null;} /** *  overrides the ToString method to show all JavaBean attribute values, omitting to write a lot of getxxx methods  */@Overridepublic  String  ToString ()  {return tostringbuilder.reflectiontostring (This,tostringstyle.multi_line_style);} @Overridepublic  boolean equals (object obj)  {if  (obj == null)  {return  false;} if  (This == obj)  {return true;} if  (!getclass (). Equals (Obj.getclass ()))  {return false;} baseentity rhs =  (baseentity)  obj;return this.id == null ? false  : this.id.equals (rhs.id);}}

Using UUID in spring data JPA