UVA 10340 all on all

Source: Internet
Author: User

Water problem, sweep from start to finish, enter two strings s and T, determine whether you can remove 0 or more characters from T (the other character order unchanged), get the string s. For example, ABCDE can get BCE, but cannot get a DC.

#include <algorithm>#include<cstring>#include<cstdio>#include<iostream>#defineLen 101000using namespacestd;CharS[len], T[len];intMain () {intsn, TN, LS, lt;  while(Cin >>s) {cin>>T; LS=strlen (s); Lt=strlen (t); SN=0; tn =0;  for(inti =0; i < ls, i < lt;i++) {            if(S[SN] = =T[tn]) {SN++; TN++; }            Else{tn++; }        }        if(sn = = ls) cout <<"Yes"<<Endl; Elsecout <<"No"<<Endl; }    return 0;}

UVA 10340 all on all

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