UVa 1339 sort ent Cipher [sort], 1339 cipher

Source: Internet
Author: User

UVa 1339 sort ent Cipher [sort], 1339 cipher

Old password for Chinese questions
You can see if you can change the location of the first character to exactly match the 26 letters of the second character.
Solution: count the number of characters in two strings. If the number of characters in each string is the same, yes is output; otherwise, no is output.
Difficulties: it is a little difficult to count the number of times each character appears.
Key Point: Sorting
Problem solving person: lingnichong
Solution time:
Experience in solving problems: a good question

1339-maximum ent CipherTime limit: 3.000 seconds

#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;char cot1[300],cot2[300];int a[30],b[30];int main(){int i,l,len1,len2;while(~scanf("%s%s",cot1,cot2)){memset(a,0,sizeof(a));memset(b,0,sizeof(b));len1=strlen(cot1);len2=strlen(cot2);if(len1>len2)    l=len1;else    l=len2;for(i=0;i<l;i++){++a[cot1[i] - 'A'];++b[cot2[i] - 'A'];}sort(a,a+26);sort(b,b+26);for(i=0;i<26;i++)if(a[i] != b[i])   break;printf(i==26?"YES\n" : "NO\n");}return 0;} 

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