Description
You had a long drive by car ahead. You had a tape recorder, but the unfortunately your best music was on CDs. You need to has it on tapes so the problem to solve is:you has a tape N minutes long. How to choose tracks from CD to get the most out of tape space and has as short unused space as possible.
Assumptions:
- Number of tracks on the CD. does not exceed 20
- No track is longer than N minutes
- Tracks do not repeat
- Length of each track was expressed as an integer number
- N Is also integer
Program should find the set of tracks which fills the tape best and print it in the same sequence as the tracks is stored On the CD
InputAny number of lines. Each one contains value
N, (after space) number of tracks and durations of the tracks. For example from first line in Sample data:
N=5, number of tracks=3, first track lasts for 1 minute, second O Ne 3 minutes, next one 4 minutes
OutputSet of tracks (and durations) which is the correct solutions and string " sum:" and sum of duration Tim Es.
Sample Input
5 3 1 3 410 4 9 8 4 220 4 10 5 7 490 8 10 23 1 2 3 4 5 745 8 4 10 44 43 12 9 8 2
Sample Output
1 4 sum:58 2 sum:1010 5 4 sum:1910 1 2 3 4 5 7 sum:554 ten 9 8 2 sum:45
Test instructions: Give a number of M and N, and then give the number of N, to choose from the n number of several and largest numbers, and sequentially output these books and the number of the and.
DFS searches and logs the path on it. You can also use 01 backpacks.
Dfs:
1#include <cstdio>2#include <cstring>3#include <algorithm>4 using namespacestd;5 intn,m,n1,sum,ans[ A],a[ A],str[ A];6 voidDfsintXintSintp)7 {8 if(s>m)return ;9 if(s>sum)Ten { Onesum=s; A for(intI=0; i<p;i++) ans[i]=Str[i]; -n1=p; - } the for(inti=x+1; i<=n;i++) - { -str[p]=A[i]; -DFS (i,s+a[i],p+1); + } - } + intMain () A { at inti; - while(~SCANF ("%d%d",&m,&N)) - { -sum=0; -n1=0; - for(i=1; i<=n;i++) scanf ("%d",&a[i]); inDfs0,0,0); - for(i=0; i<n1;i++) printf ("%d", Ans[i]); toprintf"sum:%d\n", sum); + } - return 0; the}
01:
1#include <cstdio>2#include <cstring>3#include <algorithm>4 using namespacestd;5 intdp[10005],v[ A][10005];6 intMain ()7 {8 intn,m,i,j;9 inta[ A];Ten while(~SCANF ("%d%d",&m,&N)) One { AMemset (DP,0,sizeof(DP)); -memset (V,0,sizeof(v)); - for(i=1; i<=n;i++) scanf ("%d",&a[i]); the for(i=n;i>=1; i--) - { - for(j=m;j>=a[i];j--) - { + if(dp[j]<dp[j-a[i]]+A[i]) - { +dp[j]=dp[j-a[i]]+A[i]; Av[i][j]=1; at } - } - } - for(i=1, j=dp[m];i<=n;i++) - { - if(V[i][j]) in { -printf"%d", A[i]); toj-=A[i]; + } - } theprintf"sum:%d\n", Dp[m]); * } $ return 0;Panax Notoginseng}
UVA 624 CD (01 backpack + print path or dfs+ record path)