Uvalive 4043 ants

KM Diagram for minimum weight matching

To ensure the minimum weight, the connected edge must be non-intersecting.

Ants

Time limit:3000 Ms

Memory limit:Unknown

64bit Io format:% LLD & % LlU

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Description

Young naturalist Bill studies ants in school. His ants feed on plant-louses that live on apple trees. Each ant colony needs its own apple tree to feed itself.

Bill has a map with coordinatesNAnt colonies andNApple trees. he knows that ants travel from their colony to their feeding places and back using chemically tagged routes. the routes cannot intersect each other or ants will get confused and get to the wrong colony or tree, thus spurring a war between colonies.

Bill wowould like to connect each ant colony to a single apple tree so that allNRoutes are non-Intersecting straight lines. In this problem such connection is always possible. Your task is to write a program that finds such connection.

On this picture ant colonies are denoted by empty circles and apple trees are denoted by filled circles. One possible connection is denoted by lines.

Input

Input has several dataset. The first line of each dataset contains a single integer numberN(1N100) -- the number of ant colonies and apple trees. It is followedNLines describingNAnt colonies, followedNLines describingNApple Trees. Each ant colony and apple tree is described by a pair of integer coordinatesXAndY(-10000X,Y10000) on a cartesian plane. All ant colonies and apple trees occupy distinct points on a plane. No three points are on the same line.

Output

For each dataset, write to the output fileNLines with one integer number on each line. The number written onI-Th line denotes the number (from 1N) Of the apple tree that is connected toII-th ant colony. Print a blank line between datasets.

Sample Input

5 -42 58 44 86 7 28 99 34 -13 -59 -47 -44 86 74 68 -75 -68 60 99 -60

Sample output

4 2 1 5 3

Source

Northeastern Europe 2007-2008

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#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#include <cmath>using namespace std;const int maxn=220;const double INF=999999999999999.;const double eps=1e-5;struct Dian{    double x,y;}white[maxn*maxn],black[maxn*maxn];int n;double g[maxn][maxn];int linker[maxn*maxn];double lx[maxn*maxn],ly[maxn*maxn];double slack[maxn*maxn];bool visx[maxn*maxn],visy[maxn*maxn];bool dfs(int x){    visx[x]=true;    for(int y=0;y<n;y++)    {        if(visy[y]) continue;        double tmp=lx[x]+ly[y]-g[x][y];        if(fabs(tmp)<eps)        {            visy[y]=true;            if(linker[y]==-1||dfs(linker[y]))            {                linker[y]=x;                return true;            }        }        else if(slack[y]>tmp)            slack[y]=tmp;    }    return false;}int KM(){    memset(linker,-1,sizeof(linker));    memset(ly,0,sizeof(ly));    for(int i=0;i<n;i++)    {        lx[i]=-INF;        for(int j=0;j<n;j++)            if(g[i][j]>lx[i])                lx[i]=g[i][j];    }    for(int x=0;x<n;x++)    {        for(int i=0;i<n;i++)            slack[i]=INF;        while(true)        {            memset(visx,false,sizeof(visx));            memset(visy,false,sizeof(visy));            if(dfs(x)) break;            double d=INF;            for(int i=0;i<n;i++)                if(!visy[i]&&d>slack[i])                    d=slack[i];            for(int i=0;i<n;i++)                if(visx[i])                    lx[i]-=d;            for(int i=0;i<n;i++)                if(visy[i])                    ly[i]+=d;                else                    slack[i]-=d;        }    }}double Dist(Dian a,Dian b){    return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));}int main(){    bool first=false;    while(scanf("%d",&n)!=EOF)    {        if(first) putchar(10);        else first=true;        for(int i=0;i<n;i++)        {            double a,b;            scanf("%lf%lf",&a,&b);            white[i]=(Dian){a,b};        }        for(int i=0;i<n;i++)        {            double a,b;            scanf("%lf%lf",&a,&b);            black[i]=(Dian){a,b};        }        for(int i=0;i<n;i++)        {            for(int j=0;j<n;j++)            {                double t=Dist(black[i],white[j]);                g[i][j]=-t;            }        }        KM();        for(int i=0;i<n;i++)        {            printf("%d\n",linker[i]+1);        }    }    return 0;}