Various sorting algorithm exercises

Source: Internet
Author: User

Recently busy ready to find a job, put the sorting algorithm before writing, write together, convenient later use, nonsense not to say, directly on the code;

#include <iostream> #include <time.h>using namespace std; #define N 100//#define SWAP (x, y) {int t;t=x;x=y;y=t ;} #define SWAP (x, y) {x=x^y;y=x^y;x=x^y;}    Radix sort void Radixsort (int data[], int n) {//auxiliary function, for the maximum number of digits of the data int d = 1;//Save the largest number of digits int p = 10;            for (int i = 0, i < n; ++i) {while (Data[i] >= p) {p *= 10;        ++d;    }}//Radix sort int *tmp = new Int[n]; int *count = new INT[10];    counter int I, j, K;    int radix = 1; for (i = 1; I <= D; i++)//D-Order {for (j = 0; J < K J + +) Count[j] = 0;//empty counter before each allocation fo        R (j = 0; J < N; j + +) {k = (Data[j]/radix)% 10;//Count the number of records in each bucket count[k]++; } for (j = 1; J <, J + +) Count[j] = Count[j-1] + count[j]; Assign the position in TMP to each bucket for (j = n-1; J >= 0; j--)//Collect all the records in the bucket sequentially into tmp {k = (Data[j]/radix)% 10            ;            TMP[COUNT[K]-1] = data[j];        count[k]--;      }  for (j = 0; J < N; j + +)//Copy the contents of the temporary array to data data[j] = Tmp[j];    Radix = radix * 10;    } delete[]tmp; Delete[]count;} Shell sort, improved insert sort int shellsort (int *number) {for (int group=n/2;group>0;group/=2) {for (int i=group;i<n;i++)// Each one is looped, so the following swaps only once {for (int j=i-group;j>=0&& (Number[j]>number[j+group]), J-=group)//can only be exchanged once at a time, It's not right to swap too much. {swap (Number[j],number[j+group]);}}} return 0;} Insert sort int insort (int *number) {/*int temp;for (int i=n-2;i>=0;i--)//Sort from large to small loop {temp=number[i];int J=i+1;while (temp >number[j]) {number[j-1]=number[j];j++;if (j==n) break;} Number[j-1]=temp;} */int temp,j;for (int i=1;i<n;i++)//Sort from small to large loop {temp=number[i];for (j=i;j>0;j--) {if (number[j-1]>temp) { NUMBER[J]=NUMBER[J-1];} Else{break;}} Number[j]=temp;} return 0;} Heap algorithm, heap sort, improved selection sort int heapsort (int *number) {//build sort heap Tree int heap[n+1]={-1111},child,parent;for (int i=1;i<=n;i++) {Heap[i]=number[i-1];child=i;parent=i/2;while (heap[child]


Various sorting algorithm exercises

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