void (*pfun (int, void (*qfun) (int))) (int)

Source: Internet
Author: User
#include <iostream>
using namespace std;
typedef void (*PF) (int);
void Fun (int a)
{
    cout << "Here is the function that the parameter is shaping fun (int)" << Endl;
}

void printf (int a)
{
    cout << "Here is the function Printf (int)" << Endl;
void (*pfun (int, void (*qfun) (int))) (int)
{
    //1. First of all, this is a function, the name of the function is Pfun, there are two parameters, one is plastic, and the other is the function pointer.
    //2. Second, the return value of this function is a pointer to a function, the type is: void (*PF) (int).
    PF q = qfun;
    (*Q) (4);
    The argument here is that the parameter is an integer and a function pointer.
    PF  p = fun;
    return p;
}
int main ()
{
    PF q = printf;//function pointer to function.
    PF p = pfun (2, q);
    (*p) (3);//Here is the test return value, which proves that the return value is a function pointer. return
    0;
}

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