What might be used in the Java race

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Large number

String s= "12345"; BigInteger c=biginteger.valueof (s);

Format output

System.out.printf ("%+8.3f\n", 3.14); "+" indicates that the output will be signed, positive +, negative-; 8.3f indicates the output floating point number, width is 8, the decimal point remains 3 valid System.out.printf ("%+-8.3f\n", 3.14);/"-" Indicates the left-aligned System.out.printf ("%08.3f\n", 3.14);//"0" 8-bit width of the auto-fill 0system.out.printf ("% (8.3f\n",-3.14);/"(" If it is negative, Auto Plus () System.out.printf ("%,f\n", 123456.78); "," the money represents the method, every three bits has a comma System.out.printf ("%x\n", 0x2a3b); Output 16 binary number System.out.printf ("% #x \ n", 0x2a3b);//output with 0x identification of 16 binary System.out.printf ("Boss: Your name is%s, age:%3d years, Salary:%,-7.2f\n", " Ajioy ", 21,36000.00); System.out.printf ("Boss: Your name%1 $ s, age:%2$ #x岁 \ n", "Ajioy", 38); "N{1}quot; indicates with nth parameter

All-in-the-process conversions

int ioct = 0567;//octal number declaration, preceded by 0 (0) int iten = 1000;//decimal number declaration int ihex = 0xabcd;//hex number declaration, preceded by 0x (0 x), x and ABCD not case sensitive System.out.println ("octal 0567 is replaced with binary: integer.tostring (ioct, 2) =" +integer.tostring (IOCT, 2)); System.out.println ("octal 0567 is replaced with binary: integer.tobinarystring (IOCT) =" +integer.tobinarystring (ioct)); System.out.println ("octal 0567 is replaced by decimal: integer.tostring (ioct, ten) =" +integer.tostring (ioct, 10)); System.out.println ("octal 0567 is replaced by decimal: integer.tostring (IOCT) =" +integer.tostring (ioct)); System.out.println ("octal 0567 is replaced with 16 binary: integer.tostring (ioct, 2) =" +integer.tostring (ioct, 16)); System.out.println ("octal 0567 is replaced with 16 binary: integer.tohexstring (IOCT) =" +integer.tohexstring (ioct)); System.out.println (); System.out.println ("Decimal 1000 is replaced with 16 binary: integer.tostring (iten,16) =" +integer.tostring (iten,16)); System.out.println ("Decimal 1000 is replaced with 16 binary: integer.tohexstring (Iten) =" +integer.tohexstring (iten)); System.out.println ("Decimal 1000 is replaced with eight binary: integer.tostring (iten,8) =" +integer.tostring (iten,8)); System.out.println ("Decimal 1000 is replaced with eight binary: Integer.tooctalstrinG (Iten) = "+integer.tooctalstring (iten)); System.out.println ("Decimal 1000 is replaced with binary: integer.tostring (iten,2) =" +integer.tostring (iten,2)); System.out.println ("Decimal 1000 is replaced with binary: integer.tobinarystring (Iten) =" +integer.tobinarystring (iten)); System.out.println (); System.out.println ("hexadecimal 0xAbcd is converted to decimal: integer.tostring (ihex,10) =" +integer.tostring (ihex,10)); System.out.println ("hexadecimal 0xAbcd is converted to decimal: integer.tostring (Ihex) =" +integer.tostring (Ihex)); System.out.println ("Hex 0xAbcd replaced with eight binary: integer.tostring (ihex,8) =" +integer.tostring (ihex,8)); System.out.println ("Hex 0xAbcd replaced with eight binary: integer.tooctalstring (Ihex) =" +integer.tooctalstring (Ihex)); System.out.println ("Hex 0xAbcd replace binary: integer.tostring (ihex,2) =" +integer.tostring (ihex,2)); System.out.println ("Hex 0xAbcd replace binary: integer.tobinarystring (Ihex) =" +integer.tobinarystring (Ihex)); System.out.println ();//You can also replace any binary integer with any other arbitrary binary System.out.println ("hex 0xAbcd replaced with seven binary: integer.tostring (ihex,7) =" + Integer.tostring (ihex,7)); Program output: Octal 0567 is replaced with binary: integer.tostring (ioct, 2) = 1,011,101,118 binary 0567 is replaced with binary: integer.tobinarystring (IOCT) = 1,011,101,118 binary 0567 loaded into decimal: integer.tostring (ioct, 10) = 3,758 binary 0567 is converted to decimal: integer.tostring (ioct) = 3,758 binary 0567 is replaced with 16 binary: integer.tostring (ioct, 2) = 1778 binary 0567 is replaced with 16 binary: integer.tohexstring (ioct) =177 decimal 1000 is replaced with 16: integer.tostring (iten,16) = 3e8 Decimal 1000 Replace with 16 binary: integer.tohexstring (iten) =3e8 decimal 1000 Replace with eight: integer.tostring (iten,8) = 17,500 binary 1000 replace with eight: integer.tooctalstring (iten) =1750 decimal 1000 Replace with binary: integer.tostring (iten,2) = 11,111,010,000 binary 1000 Replace with binary: integer.tobinarystring (iten) = 11,111,010,006 binary 0XABCD converted to decimal: integer.tostring (ihex,10) = 439,816 binary 0XABCD converted to decimal: integer.tostring (ihex) = 439,816 binary 0xAbcd loaded into eight binary: integer.tostring (ihex,8) = 1,257,156 binary 0XABCD replaced with eight binary: integer.tooctalstring (ihex) = 1,257,156 binary 0xAbcd loaded into binary: integer.tostring (ihex,2) = 1,.01,010,111,100,11e,+16 binary 0XABCD Replace with binary: integer.tobinarystring (Ihex) = 1,.01,010,111,100,11e,+16 binary 0XABCD Replace with seven: Integer.tostring (ihex,7) =242140

　　

What might be used in the Java race