When doing PHP query database-How to solve

When you do a PHP query database---
In the PHP query database, I passed the parameter to get the ID of a table, how can I use this ID to display the table of a certain field value;

Can also understand this: there is a user table, the field inside the Id,user,time,title, I now know the user ID, I want to take out the user table inside the Time,title these two fields, the MySQL database query, how should write the statement?????

Our project manager did not realize for a long while, seek the master to solve


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------Solution--------------------
SELECT time,title from User WHERE id= ' incoming ID value '
------Solution--------------------
$rs = mysql_query ("Select Time,title from User WHERE id= ' $id '");
$row = Mysql_fetch_assoc ($RS);
echo $row [' time '], ', $row [' Title '];
------Solution--------------------

The MYSQL_FETCH_ASSOC () function obtains a row from the result set as an associative array.

Returns an associative array based on the rows obtained from the result set, or False if there are no more rows.

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