When I use php to output a json field, I need to output two json data, but the front-end cannot obtain

Source: Internet
Author: User
When I use php to output a json field, I need to output two json data, but the front-end cannot obtain my code as follows. please give me some advice !! $ QunList = $ songGuoEr-& gt; findCountTestQuesMainListByTestId ($ testId, $ offset, 1); $ optionsList = $ son when I use php to output a json field, two json data needs to be output, but the foreground cannot obtain
My code is as follows. please give me some advice !!
$ QunList = $ songGuoEr-> findCountTestQuesMainListByTestId ($ testId, $ offset, 1 );
$ OptionsList = $ songGuoEr-> findCountTestQuesOptionsListByQuesId ($ qunList-> quesId );
Echo json_encode ($ qunList );
Echo json_encode ($ optionsList );
Thank you !!

------ Solution --------------------
Echo json_encode (array ($ qunList, $ optionsList ));

Of course, you have to change the front-end.

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