Who can talk about the use of __call?

__call only two parameters? Why does this code pass several parameters?
I see someone say that. __call the first parameter, $m, is the method you want to call test. I can't understand that. The first parameter is not a 1?

  
   x;    }}$foo = new Caller();$a = $foo->test(1, "2", 3.4, true);var_dump($a);?>

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__call only two parameters? Why does this code pass several parameters?
I see someone say that. __call the first parameter, $m, is the method you want to call test. I can't understand that. The first parameter is not a 1?

  
   x;    }}$foo = new Caller();$a = $foo->test(1, "2", 3.4, true);var_dump($a);?>

__callis called when an undefined method is called.

That is, if your test method is undefined, the test method name is passed in as __call the first argument, and test the parameter is passed in as __call the second parameter in the array.

So when you call $foo->test(1, "2", 3.4, true) , it's actually the equivalent of a call $foo->__call('test', array(1, "2", 3.4, true)) .

The __call method is triggered when a method of the class is called, such as:

  
   "后面的字符串，$parameters是通过这个方法传过来的参数    }}$google = new google();$keyword = 'VR';$google->search($keyword);//当调用当前对象不存在的方法时，会转向__call$google->operate();

With __call, you can do some encapsulation to invoke other objects and methods.
Attached official reference: PHP Magic method

The first parameter is the function name of the non-existent method that you call, and the second is a pair of arguments that you call a non-existent method simultaneous

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