Why does C use array parameters as pointers for programming? array/pointer arguments

Why does C use array parameters as pointers for programming? array/pointer arguments

#include
 
  void print_array_test(char ca[]){        printf("ca : %s\n",ca);        printf("&ca : %s\n",&ca);        printf("&(ca[0]) : %s\n",&(ca[0]));        printf("&(ca[1]) : %s\n",&(ca[1]));        printf("*(ca+0) : %c\n",*(ca+0));        printf("*(ca+1) : %c\n",*(ca+1));        printf("ca+1 : %s\n",ca+1);}void print_ptr_test(char *pa){        printf("pa : %s\n",pa);        printf("&pa : %s\n",&pa);        printf("&(pa[0]) : %s\n",&(pa[0]));        printf("&(pa[1]) : %s\n",&(pa[1]));        printf("pa+1 : %s\n",pa+1);        printf("pa[1] : %c\n",pa[1]);        printf("*(pa+1) : %c\n",*(pa+1));        printf("++pa : %s\n",++pa);}int main(){        char abc[]="hello,world!";        print_array_test(abc);        print_ptr_test(abc);        return 0;}
 

Array abc [20] = "hello, world! "

And abc [I] have the same meaning as abc + I -- the address of abc [I] is used.

Pointer pa = abc;

Pa [I] is equivalent to * (pa + I) -- the value of abc [I] is used.

In view of the above program, run:

[Root @ localhost code] #./arrayandptr
Ca: hello, world!
& Ca :???,??;
& (Ca [0]): hello, world!
& (Ca [1]): ello, world!
* (Ca + 0): h
* (Ca + 1): e
Ca + 1: ello, world!
Pa: hello, world!
& Pa :???,??;
& (Pa [0]): hello, world!
& (Pa [1]): ello, world!
Pa + 1: ello, world!
Pa [1]: e
* (Pa + 1): e
++ Pa: ello, world!
[Root @ localhost code] #