Write a function itob (int num,char s[], int n) and convert the integer num to the number of n binary. Saved to S.

Write a function itob (int num,char s[], int n) and convert the integer num to the number of n binary. Saved to S.

In the subject, the binary, octal and decimal algorithm, the same way, take the mode, output the number of each position, followed by reverse output. In hex "0123456789abcdef" [num%16], find out the numbers.

#include <stdio.h>void reverse (int len,char arr[])  //reverse { int left =0;  int right =len -1; while (left < right)  {  char temp  = arr[left];    arr[left] = arr[right];  arr[right] =  temp;  right --;  left ++;    }}void itob (int  num,char s[], int n)   //Output { int i=0; while (num) in n-binary form     {  if (n<10)   {    s[i]=num% n+ ' 0 ';       num /= n ; //die Removal    i++;  }  else  if (n==16)   {   s[i]= "0123456789abcdef" [num%16];   num/=16;    i++;  }   else  {   break;   }  } s[i]= ' &nbsp ';; reverse (i , s);} Int main () { char s[32]; int n=0; int num; scanf ("%d", &n);  printf ("num="); &NBSP;SCANF ("%d", &num);  itob (num,s, n);     printf ("%s\n", s);  return 0;}

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Write a function itob (int num,char s[], int n) and convert the integer num to the number of n binary. Saved to S.