time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7.
For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are
not.
Unfortunately, not all numbers are lucky. Petya calls a number nearly lucky if the number of lucky digits in it is a lucky number. He wonders whether number n is
a nearly lucky number.
Input
The only line contains an integer n (1 ≤ n ≤ 1018).
Please do not use the %lld specificator to read or write 64-bit numbers in С++. It is preferred to use the cin, cout streams or the %I64d specificator.
Output
Print on the single line "YES" if n is a nearly lucky
number. Otherwise, print "NO" (without the quotes).
Sample test(s)input
40047
output
NO
input
7747774
output
YES
input
1000000000000000000
output
NO
Note
In the first sample there are 3 lucky digits (first one and last two), so the answer is "NO".
In the second sample there are 7 lucky digits, 7 is lucky number, so the answer is "YES".
In the third sample there are no lucky digits, so the answer is "NO".
解題說明:此題不要被題目輸入資訊誤導了,不是要把輸入的數當成一個很大的數,而是應該看成一個字串,然後從中找出4和7的個數統計即可,最後在用模10來計算個數是否為幸運數
#include <iostream>#include<cstdio>#include<cstring>#include<cmath>using namespace std;int main(){char a[20];int i,sum;int flag;sum=0;flag=0;scanf("%s",&a);for(i=0;a[i]!='\0';i++){if(a[i]=='4'||a[i]=='7'){sum++;}}if(sum==0){flag=1;}else{while(1){if(sum%10!=4&&sum%10!=7){flag=1;break;}sum=sum/10;if(sum==0){break;}}}if(flag==0){printf("YES\n");}else{printf("NO\n");}return 0;}