關於PHP讀取時間號碼問題

public function pai3(&$actionNo, &$actionTime, $time=null){$this->setTimeNo($actionTime, $time);//echo $actionTime,' ',date('Y-m-d H:i:s', $time);if($actionTime >= date('Y-m-d H:i:s', $time)){$actionNo = date('Yz', $time)-6;}else{$actionNo = date('Yz', $time)-6;$actionTime=date('Y-m-d 18:30', $time);}}

上面代碼讀取的年和號，如201456我想改成2014056增加一位，請問怎麼改？

回複討論(解決方案)

$year = date('Y', time());$day = str_pad(date('z',time()),3,'0',STR_PAD_LEFT);echo $year.$day;

$year = date('Y', time());$day = str_pad(date('z',time()),3,'0',STR_PAD_LEFT);echo $year.$day;

能加到我代碼上發給我下嗎

public function pai3(&$actionNo, &$actionTime, $time=null){$this->setTimeNo($actionTime, $time);//echo $actionTime,' ',date('Y-m-d H:i:s', $time);$year = date('Y', $time);$day = str_pad(date('z',$time),3,'0',STR_PAD_LEFT);$times = $year.$day;if($actionTime >= date('Y-m-d H:i:s', $time)){$actionNo = $times-6;}else{$actionNo = $times-6;$actionTime=date('Y-m-d 18:30', $time);}}

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