iOS 十六進位的相加取反

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ios中將NSstring字串轉換成char類型

NSString *string = [NSString stringWithFormat:@"5D"];        const char *result = [string UTF8String];

 

char字元轉成NSstring

char a[10] = "3Er4";        NSString *string = [NSString stringWithUTF8String:a];

 

將char類型字元轉成十進位類型,然後需要什麼樣的進位類型都可以直接轉換了

unsigned long num = strtoul(result, 0, 16);        NSLog(@"%lu",num);        NSLog(@"%0lx",num);        NSLog(@"%0lX",num);

%0x----是儲存成十六進位的(字母是小寫)

%0X----是儲存成十六進位的(字母是大寫)

 

十六進位相加 取反

unsigned long num1 = strtoul([@"5D" UTF8String],0,16);unsigned long num2 = strtoul([@"EE" UTF8String],0,16);unsigned long num3 = strtoul([@"22" UTF8String],0,16);unsigned long num4 = strtoul([@"01" UTF8String],0,16);    // 進位相加Byte A = num1 + num2 + num3 + num4;// 取反Byte B = ~A;// 轉成十六進位NSString *string = [NSString stringWithFormat:@"%0X",B];

 

iOS 十六進位的相加取反

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