在擷取的結果中增加一個對象名稱

來源:互聯網
上載者:User
關鍵字 php
目前擷取到的結果是 如樣本1 結構 ,
表中沒有value欄位
$tree = M('Kind')->where(array('status'=>1))->field('id, title as name')->select();
$this->ajaxReturn($tree);
想要擷取 如樣本2 的結構,有方便的方法嗎?
架構是 thinkphp

//樣本1[  {"id": "4","name": "服飾鞋類箱包"},  {"id": "8","name": "母嬰"}]
//樣本2[    {"value":{"id":4,"name":"服飾鞋類箱包" }},    {"value":{ "id":8,"name":"母嬰"}}]

回複內容:

目前擷取到的結果是 如樣本1 結構 ,
表中沒有value欄位
$tree = M('Kind')->where(array('status'=>1))->field('id, title as name')->select();
$this->ajaxReturn($tree);
想要擷取 如樣本2 的結構,有方便的方法嗎?
架構是 thinkphp

//樣本1[  {"id": "4","name": "服飾鞋類箱包"},  {"id": "8","name": "母嬰"}]
//樣本2[    {"value":{"id":4,"name":"服飾鞋類箱包" }},    {"value":{ "id":8,"name":"母嬰"}}]

$tree = M('Kind')->where(array('status'=>1))->field('id, title as name')->select();$return_data = array();foreach ($tree as $val){    $return_data[] = array("value" => $val);}$this->ajaxReturn($return_data);
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