ajax與php傳遞和接收變數的實現代碼

$.ajax({ url: 'query.php', data: {id:10}, datatype: json success: function(results) { if (results.msg == 'success') { for (var i in data) { $('#content').append( 'id = ' + results.data[i].id + ', description = ' + results.data[i].description + ', msrp = ' + results.data[i].msrp ); } } else { $('#content').append(results.msg); } } }); 複製代碼 php代碼： if (isset($_GET['id'])) { $sql = "SELECT id, description, msrp FROM tbl WHERE id = '{$_GET['id']}'"; $return = array(); if ($result = mysql_query($sql)) { if (mysql_num_rows($result)) { $return['msg'] = 'success'; while ($row = mysql_fetch_assoc($result)) { $return['data'][] = $row; } } else { $return['msg'] = 'No results found'; } else { $return['msg'] = 'Query failed'; } header("Content-type: application/json"); echo json_encode($result); } 複製代碼

