Ajax提交Json字串,.net還原序列化成Model對象

1.建立Model對象

/// <summary>    /// 使用者實體類    /// </summary>    public class UserModel    {        /// <summary>        /// 使用者ID        /// </summary>        public long UserID { get; set; }        /// <summary>        /// 使用者顯示名        /// </summary>        public string DisplayName { get; set; }        /// <summary>        /// 使用者名稱        /// </summary>        public string RealName { get; set; }    }

2.建立Json序列化協助類

/* ============================================================================== * 功能描述：JsonHelper   * 創 建 者：RES-WUZHOU * 建立日期：2012/6/21 17:17:08 * ==============================================================================*/using System;using System.Collections.Generic;using System.Linq;using System.Text;using System.Runtime.Serialization.Json;using System.IO;using System.Web.Script.Serialization;namespace Common{    /// <summary>    /// JsonHelper    /// </summary>    public class JsonHelper    {        /// <summary>        /// JSON序列化        /// </summary>        /// <typeparam name="T"></typeparam>        /// <param name="entity"></param>        /// <returns></returns>        public static string JsonSerializer<T>(T entity)        {            var serializer = new JavaScriptSerializer();            return serializer.Serialize(entity);        }        /// <summary>        /// JSON還原序列化        /// </summary>        /// <typeparam name="T"></typeparam>        /// <param name="jsonString"></param>        /// <returns></returns>        public static T JsonDeserialize<T>(string jsonString)        {                        var serializer = new JavaScriptSerializer();            return serializer.Deserialize<T>(jsonString);        }    }}

注意:手動引用 System.Web.Script.Serialization.dll

3.後台 CS方法

 public ActionResult Add(string strUserModel)        {            UserModel userModel = JsonHelper.JsonDeserialize<UserModel>(strUserModel);    //....        }    

4.前台ajax提交

var userModel = {};userModel.UserID=1;userModel.DisplayName = "張三";userModel.RealName= "zhang";$.ajax({                url: "/user/add",                type: "post",                data: { strUserModel: $.toJSON(userModel) },                success: function (json) {                                         alert('成功');                },                error: function () {                    alert("系統異常!");                }            });

注意：頁面需引用jquery.js和jquery.json.js