1.index.php
<html><head><script language="JavaScript" type="text/javascript" src="js/jquery.js"></script><script language="JavaScript" type="text/javascript" src="js/jquery.timer.js"></script><script type="text/JavaScript">$(document).ready(function(){ $('#submitbt').click(function(){ //var name = $('#name').val(); //var dataString = "name="+name; var dataPass = { 'name': $("#name").val() }; $.ajax({ type: "POST", url: "post.php", //data: dataString, 字串傳值方式 data: dataPass,//json傳值方式 success: function (data) { alert(data);var re = $.parseJSON(data || "null"); console.log(re); } }); });});</script></head><body><form id="form" name="form" id="myform" method="post"><label>Name</label> <input name="name" type="text" id="name" /> <input type="button" class="button" id="submitbt" value="submit" > </form></body></html>
2.data.php
<?php$name = $_POST['name'];echo json_encode(array('name'=>$name));//為什麼return就不行呢。?>
參考:檢測json格式: http://jsonlint.com/