php 的一個演算法問題

來源:互聯網
上載者:User
有這樣一個數組
$arr = array(
array('a_1','a_2'),
array('b_1','b_2'),
array('c_1','c_2')
);
最後能計算成下面這個樣子。
array(
'a_1,b_1,c_1',
'a_1,b_1,c_2',
'a_1,b_2,c_1',
'a_1,b_2,c_2',
'a_2,b_1,c_1',
'a_2,b_1,c_2',
'a_2,b_2,c_1',
'a_2,b_2,c_2',
);
就是讓數組裡的每一個元素和其他元素組合。


回複討論(解決方案)

function foo($d) {  $r = array_pop($d);  while($d) {    $t = array();    $s = array_pop($d);    if(! is_array($s)) $s = array($s);    foreach($s as $x) {      foreach($r as $y) $t[] = array_merge(array($x), is_array($y) ? $y : array($y));    }    $r = $t;  }  return $r;}$ary = array(    'a'=>array('a_1','a_2'),    'b'=>array('b_1','b_2'),    'c'=>array('c_1','c_2'),);print_r(foo($ary));
Array(    [0] => Array        (            [0] => a_1            [1] => b_1            [2] => c_1        )    [1] => Array        (            [0] => a_1            [1] => b_1            [2] => c_2        )    [2] => Array        (            [0] => a_1            [1] => b_2            [2] => c_1        )    [3] => Array        (            [0] => a_1            [1] => b_2            [2] => c_2        )    [4] => Array        (            [0] => a_2            [1] => b_1            [2] => c_1        )    [5] => Array        (            [0] => a_2            [1] => b_1            [2] => c_2        )    [6] => Array        (            [0] => a_2            [1] => b_2            [2] => c_1        )    [7] => Array        (            [0] => a_2            [1] => b_2            [2] => c_2        ))

感謝,這個演算法叫什麼名來的?

叫做 笛卡爾積

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