Oracle巢狀表格儲存格式淺析,oracle嵌套
Oracle巢狀表格很少用,下面來研究下其如何儲存的。用一個例子,一個使用者對應對個部門。
SQL> select * from v$version;
BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
PL/SQL Release 11.2.0.1.0 - Production
CORE 11.2.0.1.0 Production
TNS for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
SQL> create type t_dept as object(
dept_id number,
dept_name varchar2(20)
)
/
SQL> create type t_dept_arry as varray(100) of t_dept
/
SQL> create table t_user(
user_id number,
user_name varchar2(10),
depts t_dept_arry
)
/
SQL> insert into t_user values(1,'張三',t_dept_arry(t_dept(100,'開發一組'),t_dept(200,'開發二組')));
SQL> insert into t_user values(2,'李四',t_dept_arry(t_dept(300,'設計一組'),t_dept(400,'設計二組')));
SQL> commit;
--要想遍曆使用者的所有部門資訊,需要用table這種特殊的形式
SQL> select user_id,user_name,d.dept_id,d.dept_name from t_user u,table(u.depts) d;
USER_ID USER_NAME DEPT_ID DEPT_NAME
---------- ---------- ---------- --------------------
1 張三 100 開發一組
1 張三 200 開發二組
2 李四 300 設計一組
2 李四 400 設計二組
dump block看看:
block_row_dump:
tab 0, row 0, @0x3f47
tl: 81 fb: --H-FL-- lb: 0x1 cc: 3
col 0: [ 2] c1 02
col 1: [ 4] d5 c5 c8 fd
col 2: [69]
00 01 00 00 00 00 00 01 00 00 00 0a e4 23 00 37 09 00 00 00 00 00 00 27 00
00 00 00 00 01 88 01 27 01 01 00 02 0f 84 01 0f 02 c2 02 08 bf aa b7 a2 d2
bb d7 e9 0f 84 01 0f 02 c2 03 08 bf aa b7 a2 b6 fe d7 e9
tab 0, row 1, @0x3ef6
tl: 81 fb: --H-FL-- lb: 0x1 cc: 3
col 0: [ 2] c1 03
col 1: [ 4] c0 ee cb c4
col 2: [69]
00 01 00 00 00 00 00 01 00 00 00 0a e4 24 00 37 09 00 00 00 00 00 00 27 00
00 00 00 00 01 88 01 27 01 01 00 02 0f 84 01 0f 02 c2 04 08 c9 e8 bc c6 d2
bb d7 e9 0f 84 01 0f 02 c2 05 08 c9 e8 bc c6 b6 fe d7 e9
end_of_block_dump
insert into t_user values(3,'王五',t_dept_arry(t_dept(500,'家')));
commit;
block_row_dump:
tab 0, row 0, @0x3f5d
tl: 59 fb: --H-FL-- lb: 0x1 cc: 3
col 0: [ 2] c1 04
col 1: [ 4] cd f5 ce e5
col 2: [47]
00 01 00 00 00 00 00 01 00 00 00 0a e4 49 00 21 09 00 00 00 00 00 00 11 00
00 00 00 00 01 88 01 11 01 01 00 01 09 84 01 09 02 c2 06 02 bc d2
end_of_block_dump
--看了上面dump的結果,一頭霧水,不知道是怎麼存的,不過在user_objects中找到線索,有個lob欄位
SQL> select object_name,object_type from user_objects s;
OBJECT_NAME OBJECT_TYPE
------------------------------ -------------------
SYS_LOB0000082685C00003$$ LOB
T_USER TABLE
T_DEPT_ARRY TYPE
T_DEPT TYPE
SQL> select column_name, segment_name, index_name
from user_lobs s
where s.table_name = 'T_USER';
COLUMN_NAM SEGMENT_NAME INDEX_NAME
---------- ------------------------------ ------------------------------
DEPTS SYS_LOB0000082685C00003$$ SYS_IL0000082685C00003$$
--再測試下跟普通的clob有什麼區別
drop table test purge;
create table test
(
id number,
t_clob clob
);
insert into test values(1,'開發一組開發二組');
insert into test values(1,'設計一組設計二組');
insert into test values(1,'家');
commit;
tab 0, row 0, @0x3f5d
tl: 59 fb: --H-FL-- lb: 0x1 cc: 2
col 0: [ 2] c1 02
col 1: [52]
00 54 00 01 02 0c 80 00 00 02 00 00 00 01 00 00 00 0a e4 4a 00 20 09 00 00
00 00 00 00 10 00 00 00 00 00 01 5f 00 53 d1 4e 00 7e c4 5f 00 53 d1 4e 8c
7e c4
LOB
Locator:
Length: 84(52)
Version: 1
Byte Length: 2
LobID: 00.00.00.01.00.00.00.0a.e4.4a
Flags[ 0x02 0x0c 0x80 0x00 ]:
Type: CLOB
Storage: BasicFile
Enable Storage in Row
Characterset Format: IMPLICIT
Partitioned Table: No
Options: VaringWidthReadWrite
Inode:
Size: 32
Flag: 0x09 [ Valid DataInRow ]
Future: 0x00 (should be '0x00')
Blocks: 0
Bytes: 16
Version: 00000.0000000001
Inline data[16]
Dump of memory from 0x00002AE680C155EC to 0x00002AE680C155FC
2AE680C155E0 D153005F [_.S.]
2AE680C155F0 C47E004E D153005F C47E8C4E [N.~._.S.N.~.]
tab 0, row 1, @0x3f22
tl: 59 fb: --H-FL-- lb: 0x1 cc: 2
col 0: [ 2] c1 02
col 1: [52]
00 54 00 01 02 0c 80 00 00 02 00 00 00 01 00 00 00 0a e4 4b 00 20 09 00 00
00 00 00 00 10 00 00 00 00 00 01 8b be 8b a1 4e 00 7e c4 8b be 8b a1 4e 8c
7e c4
LOB
Locator:
Length: 84(52)
Version: 1
Byte Length: 2
LobID: 00.00.00.01.00.00.00.0a.e4.4b
Flags[ 0x02 0x0c 0x80 0x00 ]:
Type: CLOB
Storage: BasicFile
Enable Storage in Row
Characterset Format: IMPLICIT
Partitioned Table: No
Options: VaringWidthReadWrite
Inode:
Size: 32
Flag: 0x09 [ Valid DataInRow ]
Future: 0x00 (should be '0x00')
Blocks: 0
Bytes: 16
Version: 00000.0000000001
Inline data[16]
Dump of memory from 0x00002AE680C155B1 to 0x00002AE680C155C1
2AE680C155B0 8BBE8B01 7E004EA1 8BBE8BC4 7E8C4EA1 [.....N.~.....N.~]
2AE680C155C0 02012CC4 [.,..]
tab 0, row 2, @0x3ef5
tl: 45 fb: --H-FL-- lb: 0x1 cc: 2
col 0: [ 2] c1 02
col 1: [38]
00 54 00 01 02 0c 80 00 00 02 00 00 00 01 00 00 00 0a e4 4c 00 12 09 00 00
00 00 00 00 02 00 00 00 00 00 01 5b b6
LOB
Locator:
Length: 84(38)
Version: 1
Byte Length: 2
LobID: 00.00.00.01.00.00.00.0a.e4.4c
Flags[ 0x02 0x0c 0x80 0x00 ]:
Type: CLOB
Storage: BasicFile
Enable Storage in Row
Characterset Format: IMPLICIT
Partitioned Table: No
Options: VaringWidthReadWrite
Inode:
Size: 18
Flag: 0x09 [ Valid DataInRow ]
Future: 0x00 (should be '0x00')
Blocks: 0
Bytes: 2
Version: 00000.0000000001
Inline data[2]
選取兩次的dump的內容,不過還是不能確定兩者是否等價:
00 01 00 00 00 00 00 01 00 00 00 0a e449 00 21 09 00 00 00 00 00 00 11 00
00 00 00 00 01 88 01 11 01 01 00 01 09 84 01 09 02 c2 06 02 bc d2
00 54 00 01 02 0c 80 00 00 0200 00 00 01 00 00 00 0a e4 4c 00 12 09 00 00
00 00 00 00 02 00 00 00 00 00 01 5b b6
總結:嵌套是通過lob在儲存嵌套的內容的,TOM說作為一種儲存機制,他更傾向於建立父子表,可以再建立一個視圖,看上去像一個真正的巢狀表格一樣,巢狀表格適合於編程構造。
在oracle中寫預存程序時兩個if嵌套要怎嵌套?格式是什樣的
IF 條件1 THEN
語句序列1;
ELSIF 條件2 THEN
語句序列2;
END IF;
oracle巢狀表格賦值問題
首先你要知道extend的用法哦,它用來為巢狀表格和變長資料擴充元素,
extend:在集合末端添加一個空元素
extend(n):在集合末端添加n個空元素
extend(n,i):把第i個元素複製n份,並添加到集合的末端。
而且如果集合沒有進行初始化的話也是不能用extend進行擴充的哦,如果擴充完成,就是追加了一個null元素,需要t_tab('cc',1,null)哦。有問題再追問吧,望採納。