先用隨便什麼東西做出個 Web Service,假設得到的Web Service地址如下:
http://192.168.0.100/android/WebService1.asmx
而這個 Web Service 中,提供了一個 Sum 函數,其實現如下:
publicint Sum(int a, int b) {
return a + b;
}
則在 Android 中,可以按以下方式調用
publicvoid callWS() throws ParserConfigurationException {
final String SERVER_URL ="http://192.168.0.100/android/WebService1.asmx/Sum";
HttpPost request =new HttpPost(SERVER_URL);
List params =new ArrayList();
params.add(new BasicNameValuePair("A", "1"));
params.add(new BasicNameValuePair("B", "2"));
try {
request.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8));
HttpResponse httpResponse =new DefaultHttpClient().execute(request);
String result ="";
if (httpResponse.getStatusLine().getStatusCode() !=404) {
result = EntityUtils.toString(httpResponse.getEntity());
}
new AlertDialog.Builder(this).setTitle("Hint").setMessage(result)
.setPositiveButton("OK", null).show();
} catch (Exception e) {
new AlertDialog.Builder(this).setTitle("Hint").setMessage(
e.getMessage()).setPositiveButton("OK", null).show();
}
}
以上方法可以正確的得到 Web Service 的傳回值,但是那是一個完整的 xml,需要進一步解析從而得到想要的結果
解析的方法如下所示:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
InputStream is =new ByteArrayInputStream(result.getBytes("UTF-8"));
Document dom = builder.parse(is);
String res = dom.getDocumentElement().getChildNodes().item(0).getNodeValue();