android 判斷輸入的是不是手機號碼

import java.io.IOException;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ClassPathResource {

 public static boolean isPhoneNumberValid(String phoneNumber) 

     boolean isValid = false;
     /*
      * 可接受的電話格式有：
      */
     String expression = "^\\(?(\\d{3})\\)?[- ]?(\\d{3})[-
]?(\\d{5})$";
     /*
      * 可接受的電話格式有：
      */
     String expression2 = "^\\(?(\\d{3})\\)?[- ]?(\\d{4})[-
]?(\\d{4})$";
     CharSequence inputStr = phoneNumber;
      Pattern pattern = Pattern.compile(expression);
     Matcher matcher = pattern.matcher(inputStr);
    
     Pattern pattern2 = Pattern.compile(expression2);
     Matcher matcher2 = pattern2.matcher(inputStr);
     if(matcher.matches() || matcher2.matches()) {
      isValid = true;
     }
     return isValid;
    }

   

 

    public static void main(String[] args) throws IOException {

        System.out.println(ClassPathResource.isPhoneNumberValid("18352662160"));

    }

}

參考：http://blog.csdn.net/boyupeng/article/details/6418074