Android ListView帶CheckBox實現單選

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這個應該是個經常會遇到的需求,網上找了很多的demo感覺說的有點太長於是自己抽空乾脆記錄一下,目前我實現listView帶CheckBox單選主要用兩種方法1,用一個bean選項組,每次getView的時候去判斷這個bean的狀態2,判斷點擊的position是否跟getView的position一致,這種辦法耦合性較低不建議使用:第1種方法:首先是我們的bean:
public class Bean {    private boolean isChecked;    private String msg = "這是一條測試資料";    public Bean(){    }    public Bean(boolean isCheched) {        this.isChecked = isCheched;    }    public boolean isChecked() {        return isChecked;    }    public void setChecked(boolean isChecked) {        this.isChecked = isChecked;    }    public String getMsg() {        return msg;    }    public void setMsg(String msg) {        this.msg = msg;    } }

然後在getView的時候判斷狀態

public View getView(int position, View convertView, ViewGroup parent) {        ViewHolder mViewHolder;        if(convertView == null){            convertView = mInfater.inflate(R.layout.list_item, null);            mViewHolder = new ViewHolder(convertView);            convertView.setTag(mViewHolder);        }else{            mViewHolder = (ViewHolder) convertView.getTag();        }        mViewHolder.mTextView.setText(mDatas.get(position).getMsg());        if(mDatas.get(position).isChecked()){//狀態選中            mViewHolder.mCheckBox.setChecked(true);        }else{            mViewHolder.mCheckBox.setChecked(false);        }        return convertView;    }
這樣我們就能通過bean的狀態來控制checkBox的選中與否了,但是onItemCLick的時候的操作才是關鍵
public class MainActivity extends ActionBarActivity {    private ListView mListView;    private ListAdapter mAdapter;    private List<Bean> mDatas;    @Override    protected void onCreate(Bundle savedInstanceState) {        super.onCreate(savedInstanceState);        setContentView(R.layout.activity_main);        mListView = (ListView) findViewById(R.id.main_listView);        mDatas = new ArrayList<Bean>();        for (int i = 0; i < 20; i++) {            if(i == 0){//預設選中第一個                mDatas.add(new Bean(true));                continue;            }            mDatas.add(new Bean(false));        }        mAdapter = new ListAdapter(this, mDatas);        mListView.setAdapter(mAdapter);        mListView.setOnItemClickListener(mOnItemClickListener);    }    private final OnItemClickListener mOnItemClickListener = new OnItemClickListener() {        @Override        public void onItemClick(AdapterView<?> adapterView, View view, int position, long arg3) {            for (Bean bean : mDatas) {//全部設為未選中                bean.setChecked(false);            }            mDatas.get(position).setChecked(true);//點擊的設為選中            mAdapter.notifyDataSetChanged();        }    };}
XML
<?xml version="1.0" encoding="utf-8"?><LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"    android:layout_width="match_parent"    android:layout_height="match_parent"    android:orientation="horizontal" >    <TextView         android:id="@+id/main_list_item_text"        android:layout_width="0dp"        android:layout_height="match_parent"        android:textColor="@android:color/black"        android:layout_weight="1"        android:gravity="center_vertical"        />    <!-- checkBox擷取事件的優先順序大於listView故需設定focusable = false -->    <CheckBox         android:id="@+id/main_list_item_checkBox"        android:layout_width="wrap_content"        android:layout_height="wrap_content"        android:layout_gravity="center_vertical"        android:backgroundTintMode="multiply"        android:layout_marginRight="10dp"          android:clickable="false"        android:focusableInTouchMode="false"        android:focusable="false"        /></LinearLayout>
於是這樣ListView的CheckBox就能實現單選了第二種:

這種辦法不推薦使用

public class MainActivity extends ActionBarActivity {    private ListView mListView;    private ListAdapter mAdapter;    private List<Bean> mDatas;    public static int pos;//記錄選中的position    @Override    protected void onCreate(Bundle savedInstanceState) {        super.onCreate(savedInstanceState);        setContentView(R.layout.activity_main);        mListView = (ListView) findViewById(R.id.main_listView);        mDatas = new ArrayList<Bean>();        for (int i = 0; i < 20; i++) {            if(i == 0){                mDatas.add(new Bean(true));                continue;            }            mDatas.add(new Bean(false));        }        mAdapter = new ListAdapter(this, mDatas);        mListView.setAdapter(mAdapter);        mListView.setOnItemClickListener(mOnItemClickListener);    }    private final OnItemClickListener mOnItemClickListener = new OnItemClickListener() {        @Override        public void onItemClick(AdapterView<?> adapterView, View view, int position, long arg3) {            pos = position;            mAdapter.notifyDataSetChanged();        }    };}
getView的時候判斷MainActivity的pos是否等於getView的position
    @Override    public View getView(int position, View convertView, ViewGroup parent) {        ViewHolder mViewHolder;        if(convertView == null){            convertView = mInfater.inflate(R.layout.list_item, null);            mViewHolder = new ViewHolder(convertView);            convertView.setTag(mViewHolder);        }else{            mViewHolder = (ViewHolder) convertView.getTag();        }        mViewHolder.mTextView.setText(mDatas.get(position).getMsg());        if(MainActivity.pos == position){//MainActivity的pos是否等於position            mViewHolder.mCheckBox.setChecked(true);        }else{            mViewHolder.mCheckBox.setChecked(false);        }        return convertView;    }
不推薦使用第二種辦法,這種辦法會讓程式的耦合性變得很低,並且全域變數始終會有一個Class 對象的控制代碼指向它除非這個Class對象要被回收了否則靜態變數是不會被GC掉以上僅是個人用法,當然也有其他辦法實現,看個人的喜好吧

Android ListView帶CheckBox實現單選

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