標籤:[] 技術 soc private com run cep 實現 問題
為什麼會有線程同步的概念呢?為什麼要同步?什麼是線程同步?先看一段代碼:
package com.maso.test;public class ThreadTest2 implements Runnable{private TestObj testObj = new TestObj();public static void main(String[] args) {ThreadTest2 tt = new ThreadTest2();Thread t1 = new Thread(tt, "thread_1");Thread t2 = new Thread(tt, "thread_2");t1.start();t2.start();}@Overridepublic void run() {for(int j = 0; j < 10; j++){int i = fix(1);try {Thread.sleep(1);} catch (InterruptedException e) {e.printStackTrace();}System.out.println(Thread.currentThread().getName() + " : i = " + i);}}public int fix(int y){return testObj.fix(y);}public class TestObj{int x = 10;public int fix(int y){return x = x - y;}}}輸出結果後,就會發現變數x被兩個線程同一時候操作。這樣就非常easy導致誤操作。
怎樣才幹解決問題呢?用線程的同步技術。加上synchronizedkeyword
public synchronized int fix(int y){return testObj.fix(y);}加上同步後,就能夠看到有序的從9輸出到-10.
假設加到TestObj類的fix方法上能不能實現同步呢?
public class TestObj{int x = 10;public synchronized int fix(int y){return x = x - y;}}假設將synchronized加到方法上則等價於
synchronized(this){}能夠推斷出兩個線程使用的TestObj類的同一個執行個體testOjb,所以後實現同步,可是輸出的結果卻不是理想的結果。這是由於當A線程運行完x = x - y後還沒有輸出則B線程已經進入開始運行x = x - y.
所以像以下這樣輸出就不會有什麼問題了:
public class TestObj{public TestObj(){System.out.println("調用了建構函式");}int x = 10;public synchronized int fix(int y){x = x - y;System.out.println(Thread.currentThread().getName() + " : x = " + x);return x;}}假設將外部的fix方法改動例如以下:
public int fix(int y){ax++ ;if(ax%2 == 0){return testObj.fix(y, testObj.str1);}else{return testObj.fix(y, testObj.str2);}}
public class TestObj{String str1 = "a1";String str2 = "a2";public TestObj(){System.out.println("調用了建構函式");}int x = 10;public int fix(int y, String str){synchronized (str) {x = x - y;System.out.println(Thread.currentThread().getName() + " : x = " + x);}return x;}}此時synchronized中的str對象不是同一個對象,所以兩個線程所持有的對象鎖不是同一個,這樣就不能實現同步。
要實現線程之間的相互排斥就要使用同一個對象鎖。
什麼是死結呢?舉個範例就是比方你和同學租了個兩室的房子,你拿著你房子的鑰匙。你同學拿著他房子的鑰匙,如今你在房子等你同學將他的鑰匙給你然後你進他房子。你同學在他的房子等你將鑰匙給他然後他進你的房子,這樣就死結了。
package com.maso.test;public class ThreadDieSock implements Runnable { private int flag = 1; private Object obj1 = new Object(), obj2 = new Object(); public void run() { System.out.println("flag=" + flag); if (flag == 1) { synchronized (obj1) { System.out.println("我已經鎖定obj1,歇息0.5秒後鎖定obj2去!"); try { Thread.sleep(500); } catch (InterruptedException e) { e.printStackTrace(); } synchronized (obj2) { System.out.println("1"); } } } if (flag == 0) { synchronized (obj2) { System.out.println("我已經鎖定obj2,歇息0.5秒後鎖定obj1去。"); try { Thread.sleep(500); } catch (InterruptedException e) { e.printStackTrace(); } synchronized (obj1) { System.out.println("0"); } } } } public static void main(String[] args) { ThreadDieSock run01 = new ThreadDieSock(); ThreadDieSock run02 = new ThreadDieSock(); run01.flag = 1; run02.flag = 0; Thread thread01 = new Thread(run01); Thread thread02 = new Thread(run02); System.out.println("線程開始嘍!"); thread01.start(); thread02.start(); }}
Android多線程研究(3)——線程同步和相互排斥及死結