用for給數組賦值

$tests=array(id => "910003", params => array("param1" => '', "param2" => '', "param3" => ''));for ($i = 0; $i <= count($tests["params"]); $i++) {   }

如何用上述方法修改param1，param2，param3值？

回複討論(解決方案)

$i <= count($tests["params"])
應為
$i < count($tests["params"])

$tests = array('id' => "910003", 'params' => array("param1" => '', "param2" => '', "param3" => ''));foreach($tests["params"] as $k=>&$t) $t = $k;print_r($tests);

Array(    [id] => 910003    [params] => Array        (            [param1] => param1            [param2] => param2            [param3] => param3        ))

$tests = array('id' => "910003", 'params' => array("param1" => '', "param2" => '', "param3" => ''));for($i=1; $i<=count($tests["params"]); $i++) {  $tests["params"]['param'.$i] = $i;}print_r($tests);

Array(    [id] => 910003    [params] => Array        (            [param1] => 1            [param2] => 2            [param3] => 3        ))

謝謝！，如果這個參數名是沒有規律的（如：param_23、paramAbc……），那有如何?

不是給了你兩個方案了嗎？

哦，明白了！謝謝！

$tests=array('id' => "910003", 'params' => array(                  "param1" => '',                   "param2" => '',                   "param3" => ''                  ));for ($i = 1; $i<=count($tests["params"]); $i++) {        $tests['params']['param'.$i]=$i;}print_r($tests['params']);

謝謝！，如果這個參數名是沒有規律的（如：param_23、paramAbc……），那有如何?

如果沒有規律，只能換一種辦法了

