C++：盾神與條狀項鏈

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實現代碼如下：

#include<cstdlib>#include <string>#include <iostream>using namespace std;int main(){    int n, m;    cin >> n >> m;    int *a = (int *)malloc(n * sizeof(n));    for (int i = 0; i < n; i++)        cin >> a[i];    //定義m次操作    for (int x = 0; x < m; x++)    {        int t1, t2;        string s;        cin >> s;        if (s == "DEL")        {            cin >> t1;            for (int i = 0; i < n; i++)            {                if (a[i] == t1)                {                    for (int j = i; j < n - 1; j++)                        a[j] = a[j + 1];                    break;                }            }            n--;        }        else if (s == "ADD")        {            n++;            cin >> t1 >> t2;            for (int i = 0; i < n-1; i++)            {                if (a[i] == t1)                {                    for (int j = n - 1; j > i; j--)                        a[j] = a[j - 1];                    a[i] = t2;                    break;                }            }        }    }    cout << n << endl;    for (int i = 0; i < n; i++)        cout << a[i] << " ";    system("PAUSE");    return 0;}

 

C++：盾神與條狀項鏈