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C#數組的排序(正序逆序)
這種排序 超級簡單的 !
using System;using System.Collections.Generic;using System.Linq;using System.Text;namespace ConsoleApplication4{ class Program { static void Main(string[] args) { string[] str = { "d","h","a","c","g","t","e","u","b"}; var lowtohigh = from p in str orderby p select p; //linq str = lowtohigh.ToArray(); foreach (var item in str) { Console.WriteLine("正序排列" + item);//正序排列 } //================================================= for (int i = 0; i < str.Length/2;i ++ ) { string temp=str[i]; //建立一個變數相互交換 str[i]=str[str.Length-i-1]; str[str.Length - i - 1] = temp;//相互交換 } foreach (var newstr in str) { Console.WriteLine("逆序排列:"+newstr); } Console.WriteLine("==================================="); //############################################### int[] num = { 5, 78, 9, 1, 8, 4, 2, 88, 3 }; var lowtohigh1 = from p in num orderby p select p; num = lowtohigh1.ToArray(); foreach (var num1 in num) { Console.WriteLine(num1);//正序排列 } for (int i = 0; i < num.Length / 2;i++ ) { int temp =num[i]; //建立一個變數相互交換 num[i] = num[num.Length - i - 1]; num [num.Length - i - 1] = temp;//相互交換 } foreach (var newnum in num) { Console.WriteLine("逆序排列:" + newnum); } Console.WriteLine("==================================="); } }}
結果: