JavaScript編程實現字元和字串翻轉

最後更新：2018-12-05 來源：互聯網

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　　今天中午在解密一個網頁木馬時寫的……

　　主要是使用了JavaScript的字串的 split 方法、數組的 reverse 和 join 方法。

<html>
<head>
<title>JavaScript編程實現字元和字串翻轉</title>
<META NAME="Author" CONTENT="PurpleEndurer">
</head>
<body>
<form name="frT">
源字串：<input type="checkbox" name="ckbRow">行間翻轉</input>　<input type="checkbox" name="ckbChar">行內字元翻轉</input>　<button onClick="reverseAll()">處理</button><BR>
<textarea name="taS" ROWS="12" COLS="90">
d321
c321
b321
a543
</textarea><BR>
轉換結果：<BR>
<BR><textarea name="taR" ROWS="12" COLS="90"></textarea>
</form>

<script language=javascript>
function reverseAll()
{
        var s1= document.frT.taS.value;
        var as1 = s1.split("/n");       //按行分成數組
        if (true==document.frT.ckbRow.checked)
        {
                as1 = as1.reverse();    //行間翻轉
        }

        var s2="";
        if (true==document.frT.ckbChar.checked)
        {
                //行內字元翻轉
                var i, t, t1;
                for (i=0; i < as1.length; i++)
                {
                        t = as1[i].split('');//把字元分成數組
                        t1 = t.reverse();//行內字元翻轉
                        s2 += t1.join('');
                }

                /*另一種實現方法
                for (i=0; i < as1.length; i++)
                {
                        t = as1[i].split('');
                        t1 = t.reverse();
                        s2 += t1.join('');
                }
                */
                s2 = s2.substr(1);
        }
        else
        {
                s2 = as1.join("");
        }
        document.frT.taR.value = s2;
}

//行間翻轉
function reverseRows()
{
        var s1= document.frT.taS.value;
        var as0 = s1.split("/n");       //按行分成數組
        var as1 = as0.reverse();        //數組翻轉
        document.frT.taR.value = as1.join("");
}

//行內字元翻轉
function reverseChar()
{
        var s1= document.frT.taS.value;
        var as0 = s1.split("/n");
        var s2="", i, t, t1;
        for (i=0; i < as0.length; i++)
        {
                t = as0[i].split('');//把字元分成數組
                t1 = t.reverse();
                s2 += t1.join('');
        }

        /*另一種實現方法
        var s2="", i, t, t1;
        for (i=0; i < as0.length; i++)
        {
                t = as0[i].split('');
                t1 = t.reverse();
                s2 += t1.join('');
        }
        */

        document.frT.taR.value = s2.substr(1);
}
</script>
</body>
</html>

本文章原先以中文撰寫並發佈於 aliyun.com，亦設英文版本，僅作資訊用途。本網站不對文章的準確性，完整性或可靠性或其任何翻譯作出任何明示或暗示的陳述或保證。如對該文章有任何疑慮或投訴，請傳送電郵至 info-contact@alibabacloud.com 並提供相關疑慮或投訴的詳細說明。職員會於 5 個工作天內與您聯絡，一經驗證之後，即會刪除該侵權內容。

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