迴圈有關問題--HELP

來源:互聯網
上載者:User
迴圈問題--HELP
求教:
表1:
db_1

fid
fup
name
---------------
表2:
db2

fid
subject
---------------
fid(表db_1)=fid(表db_2)
--------------------------------
我是想迴圈列出表1中 fup=0 的name以及跟name相關的subject。


――――――――――――――――――――――――
|
| name1 | name2 | name3 | name4
|subject subject subject subject
|subject subject subject subject
|subject subject subject subject
|subject subject subject subject
|subject subject subject subject
|subject subject subject subject
|

------解決方案--------------------
select db_1.name,db_2.subject from db_1,db_2 where db_1.fid=db_2.fid and db_1.fup=0
group by db_1.name,db_2.subject
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