python實現的使用gmail發郵件的程式碼片段

找到個用python寫的使用gmail發郵件的代碼，挺好用的，當然錯誤處理都沒做，先記錄下來：View Code

 1 import os 2 import smtplib 3 import mimetypes 4 from email.MIMEMultipart import MIMEMultipart 5 from email.MIMEBase import MIMEBase 6 from email.MIMEText import MIMEText 7 from email.MIMEAudio import MIMEAudio 8 from email.MIMEImage import MIMEImage 9 from email.Encoders import encode_base6410 11 def sendMail(subject, text, *attachmentFilePaths):12   gmailUser = 'youraccount@gmail.com'13   gmailPassword = 'yourpasswd'14   recipient = 'mail1@gmail.com;mail2@gmail.com'15 16   msg = MIMEMultipart()17   msg['From'] = gmailUser18   msg['To'] = recipient19   msg['Subject'] = subject20   msg.attach(MIMEText(text))21 22   for attachmentFilePath in attachmentFilePaths:23     msg.attach(getAttachment(attachmentFilePath))24 25   mailServer = smtplib.SMTP('smtp.gmail.com', 587)26   mailServer.ehlo()27   mailServer.starttls()28   mailServer.ehlo()29   mailServer.login(gmailUser, gmailPassword)30   mailServer.sendmail(gmailUser, recipient, msg.as_string())31   mailServer.close()32 33   print('Sent email to %s' % recipient)34 35 def getAttachment(attachmentFilePath):36   contentType, encoding = mimetypes.guess_type(attachmentFilePath)37 38   if contentType is None or encoding is not None:39     contentType = 'application/octet-stream'40 41   mainType, subType = contentType.split('/', 1)42   file = open(attachmentFilePath, 'rb')43 44   if mainType == 'text':45     attachment = MIMEText(file.read())46   elif mainType == 'message':47     attachment = email.message_from_file(file)48   elif mainType == 'image':49     attachment = MIMEImage(file.read(),_subType=subType)50   elif mainType == 'audio':51     attachment = MIMEAudio(file.read(),_subType=subType)52   else:53     attachment = MIMEBase(mainType, subType)54   attachment.set_payload(file.read())55   encode_base64(attachment)56 57   file.close()58 59   attachment.add_header('Content-Disposition', 'attachment',   filename=os.path.basename(attachmentFilePath))60   return attachment